Metamath Proof Explorer


Theorem pcoptcl

Description: A constant function is a path from Y to itself. (Contributed by Mario Carneiro, 12-Feb-2015) (Revised by Mario Carneiro, 19-Mar-2015)

Ref Expression
Hypothesis pcopt.1 ⊢ 𝑃 = ( ( 0 [,] 1 ) × { 𝑌 } )
Assertion pcoptcl ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( 𝑃 ∈ ( II Cn 𝐽 ) ∧ ( 𝑃 ‘ 0 ) = 𝑌 ∧ ( 𝑃 ‘ 1 ) = 𝑌 ) )

Proof

Step Hyp Ref Expression
1 pcopt.1 ⊢ 𝑃 = ( ( 0 [,] 1 ) × { 𝑌 } )
2 iitopon ⊢ II ∈ ( TopOn ‘ ( 0 [,] 1 ) )
3 cnconst2 ⊢ ( ( II ∈ ( TopOn ‘ ( 0 [,] 1 ) ) ∧ 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( ( 0 [,] 1 ) × { 𝑌 } ) ∈ ( II Cn 𝐽 ) )
4 2 3 mp3an1 ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( ( 0 [,] 1 ) × { 𝑌 } ) ∈ ( II Cn 𝐽 ) )
5 1 4 eqeltrid ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → 𝑃 ∈ ( II Cn 𝐽 ) )
6 1 fveq1i ⊢ ( 𝑃 ‘ 0 ) = ( ( ( 0 [,] 1 ) × { 𝑌 } ) ‘ 0 )
7 simpr ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → 𝑌 ∈ 𝑋 )
8 0elunit ⊢ 0 ∈ ( 0 [,] 1 )
9 fvconst2g ⊢ ( ( 𝑌 ∈ 𝑋 ∧ 0 ∈ ( 0 [,] 1 ) ) → ( ( ( 0 [,] 1 ) × { 𝑌 } ) ‘ 0 ) = 𝑌 )
10 7 8 9 sylancl ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( ( ( 0 [,] 1 ) × { 𝑌 } ) ‘ 0 ) = 𝑌 )
11 6 10 eqtrid ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( 𝑃 ‘ 0 ) = 𝑌 )
12 1 fveq1i ⊢ ( 𝑃 ‘ 1 ) = ( ( ( 0 [,] 1 ) × { 𝑌 } ) ‘ 1 )
13 1elunit ⊢ 1 ∈ ( 0 [,] 1 )
14 fvconst2g ⊢ ( ( 𝑌 ∈ 𝑋 ∧ 1 ∈ ( 0 [,] 1 ) ) → ( ( ( 0 [,] 1 ) × { 𝑌 } ) ‘ 1 ) = 𝑌 )
15 7 13 14 sylancl ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( ( ( 0 [,] 1 ) × { 𝑌 } ) ‘ 1 ) = 𝑌 )
16 12 15 eqtrid ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( 𝑃 ‘ 1 ) = 𝑌 )
17 5 11 16 3jca ⊢ ( ( 𝐽 ∈ ( TopOn ‘ 𝑋 ) ∧ 𝑌 ∈ 𝑋 ) → ( 𝑃 ∈ ( II Cn 𝐽 ) ∧ ( 𝑃 ‘ 0 ) = 𝑌 ∧ ( 𝑃 ‘ 1 ) = 𝑌 ) )