Metamath Proof Explorer


Theorem phoeqi

Description: A condition implying that two operators are equal. (Contributed by NM, 25-Jan-2008) (New usage is discouraged.)

Ref Expression
Hypotheses ip2eqi.1 ⊢ 𝑋 = ( BaseSet ‘ 𝑈 )
ip2eqi.7 ⊢ 𝑃 = ( ·𝑖OLD ‘ 𝑈 )
ip2eqi.u ⊢ 𝑈 ∈ CPreHilOLD
Assertion phoeqi ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑇 : 𝑌 ⟶ 𝑋 ) → ( ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑌 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ 𝑆 = 𝑇 ) )

Proof

Step Hyp Ref Expression
1 ip2eqi.1 ⊢ 𝑋 = ( BaseSet ‘ 𝑈 )
2 ip2eqi.7 ⊢ 𝑃 = ( ·𝑖OLD ‘ 𝑈 )
3 ip2eqi.u ⊢ 𝑈 ∈ CPreHilOLD
4 ralcom ⊢ ( ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑌 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ ∀ 𝑦 ∈ 𝑌 ∀ 𝑥 ∈ 𝑋 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) )
5 ffvelcdm ⊢ ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑦 ∈ 𝑌 ) → ( 𝑆 ‘ 𝑦 ) ∈ 𝑋 )
6 ffvelcdm ⊢ ( ( 𝑇 : 𝑌 ⟶ 𝑋 ∧ 𝑦 ∈ 𝑌 ) → ( 𝑇 ‘ 𝑦 ) ∈ 𝑋 )
7 1 2 3 ip2eqi ⊢ ( ( ( 𝑆 ‘ 𝑦 ) ∈ 𝑋 ∧ ( 𝑇 ‘ 𝑦 ) ∈ 𝑋 ) → ( ∀ 𝑥 ∈ 𝑋 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ ( 𝑆 ‘ 𝑦 ) = ( 𝑇 ‘ 𝑦 ) ) )
8 5 6 7 syl2an ⊢ ( ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑦 ∈ 𝑌 ) ∧ ( 𝑇 : 𝑌 ⟶ 𝑋 ∧ 𝑦 ∈ 𝑌 ) ) → ( ∀ 𝑥 ∈ 𝑋 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ ( 𝑆 ‘ 𝑦 ) = ( 𝑇 ‘ 𝑦 ) ) )
9 8 anandirs ⊢ ( ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑇 : 𝑌 ⟶ 𝑋 ) ∧ 𝑦 ∈ 𝑌 ) → ( ∀ 𝑥 ∈ 𝑋 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ ( 𝑆 ‘ 𝑦 ) = ( 𝑇 ‘ 𝑦 ) ) )
10 9 ralbidva ⊢ ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑇 : 𝑌 ⟶ 𝑋 ) → ( ∀ 𝑦 ∈ 𝑌 ∀ 𝑥 ∈ 𝑋 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ ∀ 𝑦 ∈ 𝑌 ( 𝑆 ‘ 𝑦 ) = ( 𝑇 ‘ 𝑦 ) ) )
11 ffn ⊢ ( 𝑆 : 𝑌 ⟶ 𝑋 → 𝑆 Fn 𝑌 )
12 ffn ⊢ ( 𝑇 : 𝑌 ⟶ 𝑋 → 𝑇 Fn 𝑌 )
13 eqfnfv ⊢ ( ( 𝑆 Fn 𝑌 ∧ 𝑇 Fn 𝑌 ) → ( 𝑆 = 𝑇 ↔ ∀ 𝑦 ∈ 𝑌 ( 𝑆 ‘ 𝑦 ) = ( 𝑇 ‘ 𝑦 ) ) )
14 11 12 13 syl2an ⊢ ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑇 : 𝑌 ⟶ 𝑋 ) → ( 𝑆 = 𝑇 ↔ ∀ 𝑦 ∈ 𝑌 ( 𝑆 ‘ 𝑦 ) = ( 𝑇 ‘ 𝑦 ) ) )
15 10 14 bitr4d ⊢ ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑇 : 𝑌 ⟶ 𝑋 ) → ( ∀ 𝑦 ∈ 𝑌 ∀ 𝑥 ∈ 𝑋 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ 𝑆 = 𝑇 ) )
16 4 15 bitrid ⊢ ( ( 𝑆 : 𝑌 ⟶ 𝑋 ∧ 𝑇 : 𝑌 ⟶ 𝑋 ) → ( ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑌 ( 𝑥 𝑃 ( 𝑆 ‘ 𝑦 ) ) = ( 𝑥 𝑃 ( 𝑇 ‘ 𝑦 ) ) ↔ 𝑆 = 𝑇 ) )