Metamath Proof Explorer


Theorem rabbi2dva

Description: Deduction from a wff to a restricted class abstraction. (Contributed by NM, 14-Jan-2014)

Ref Expression
Hypothesis rabbi2dva.1 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝑥 ∈ 𝐵 ↔ 𝜓 ) )
Assertion rabbi2dva ( 𝜑 → ( 𝐴 ∩ 𝐵 ) = { 𝑥 ∈ 𝐴 ∣ 𝜓 } )

Proof

Step Hyp Ref Expression
1 rabbi2dva.1 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝑥 ∈ 𝐵 ↔ 𝜓 ) )
2 dfin5 ⊢ ( 𝐴 ∩ 𝐵 ) = { 𝑥 ∈ 𝐴 ∣ 𝑥 ∈ 𝐵 }
3 1 rabbidva ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝑥 ∈ 𝐵 } = { 𝑥 ∈ 𝐴 ∣ 𝜓 } )
4 2 3 eqtrid ⊢ ( 𝜑 → ( 𝐴 ∩ 𝐵 ) = { 𝑥 ∈ 𝐴 ∣ 𝜓 } )