Metamath Proof Explorer


Theorem relcnvtrg

Description: Subclass law for converse of a composition. A particular case is ( ( R o. R ) C_ R <-> (`' R o. ``' R ) C_ ``' R ) ` , which says that a relation is transitive iff its converse is transitive. (Contributed by FL, 19-Sep-2011) Generalize to a statement about three classes rather than one. (Revised by Peter Mazsa, 17-Oct-2023) Remove antecedent. (Revised by Eric Schmidt, 8-Aug-2026)

Ref Expression
Assertion relcnvtrg ( ( 𝑅 ∘ 𝑆 ) ⊆ 𝑇 ↔ ( ◡ 𝑆 ∘ ◡ 𝑅 ) ⊆ ◡ 𝑇 )

Proof

Step Hyp Ref Expression
1 cnvco ⊢ ◡ ( 𝑅 ∘ 𝑆 ) = ( ◡ 𝑆 ∘ ◡ 𝑅 )
2 cnvss ⊢ ( ( 𝑅 ∘ 𝑆 ) ⊆ 𝑇 → ◡ ( 𝑅 ∘ 𝑆 ) ⊆ ◡ 𝑇 )
3 1 2 eqsstrrid ⊢ ( ( 𝑅 ∘ 𝑆 ) ⊆ 𝑇 → ( ◡ 𝑆 ∘ ◡ 𝑅 ) ⊆ ◡ 𝑇 )
4 cnvco ⊢ ◡ ( ◡ 𝑆 ∘ ◡ 𝑅 ) = ( ◡ ◡ 𝑅 ∘ ◡ ◡ 𝑆 )
5 cocnvcnv1 ⊢ ( ◡ ◡ 𝑅 ∘ ◡ ◡ 𝑆 ) = ( 𝑅 ∘ ◡ ◡ 𝑆 )
6 cocnvcnv2 ⊢ ( 𝑅 ∘ ◡ ◡ 𝑆 ) = ( 𝑅 ∘ 𝑆 )
7 4 5 6 3eqtri ⊢ ◡ ( ◡ 𝑆 ∘ ◡ 𝑅 ) = ( 𝑅 ∘ 𝑆 )
8 cnvss ⊢ ( ( ◡ 𝑆 ∘ ◡ 𝑅 ) ⊆ ◡ 𝑇 → ◡ ( ◡ 𝑆 ∘ ◡ 𝑅 ) ⊆ ◡ ◡ 𝑇 )
9 7 8 eqsstrrid ⊢ ( ( ◡ 𝑆 ∘ ◡ 𝑅 ) ⊆ ◡ 𝑇 → ( 𝑅 ∘ 𝑆 ) ⊆ ◡ ◡ 𝑇 )
10 cnvcnvss ⊢ ◡ ◡ 𝑇 ⊆ 𝑇
11 9 10 sstrdi ⊢ ( ( ◡ 𝑆 ∘ ◡ 𝑅 ) ⊆ ◡ 𝑇 → ( 𝑅 ∘ 𝑆 ) ⊆ 𝑇 )
12 3 11 impbii ⊢ ( ( 𝑅 ∘ 𝑆 ) ⊆ 𝑇 ↔ ( ◡ 𝑆 ∘ ◡ 𝑅 ) ⊆ ◡ 𝑇 )