Metamath Proof Explorer


Theorem rntrcl

Description: The range of the transitive closure is equal to the range of its base relation. (Contributed by RP, 1-Nov-2020)

Ref Expression
Assertion rntrcl ( 𝑋 ∈ 𝑉 → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } = ran 𝑋 )

Proof

Step Hyp Ref Expression
1 trclubg ⊢ ( 𝑋 ∈ 𝑉 → ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) )
2 rnss ⊢ ( ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) )
3 1 2 syl ⊢ ( 𝑋 ∈ 𝑉 → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) )
4 rnun ⊢ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) = ( ran 𝑋 ∪ ran ( dom 𝑋 × ran 𝑋 ) )
5 rnxpss ⊢ ran ( dom 𝑋 × ran 𝑋 ) ⊆ ran 𝑋
6 ssequn2 ⊢ ( ran ( dom 𝑋 × ran 𝑋 ) ⊆ ran 𝑋 ↔ ( ran 𝑋 ∪ ran ( dom 𝑋 × ran 𝑋 ) ) = ran 𝑋 )
7 5 6 mpbi ⊢ ( ran 𝑋 ∪ ran ( dom 𝑋 × ran 𝑋 ) ) = ran 𝑋
8 4 7 eqtri ⊢ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) = ran 𝑋
9 3 8 sseqtrdi ⊢ ( 𝑋 ∈ 𝑉 → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ran 𝑋 )
10 ssmin ⊢ 𝑋 ⊆ ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) }
11 rnss ⊢ ( 𝑋 ⊆ ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } → ran 𝑋 ⊆ ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } )
12 10 11 mp1i ⊢ ( 𝑋 ∈ 𝑉 → ran 𝑋 ⊆ ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } )
13 9 12 eqssd ⊢ ( 𝑋 ∈ 𝑉 → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } = ran 𝑋 )