Step |
Hyp |
Ref |
Expression |
1 |
|
trclubg |
⊢ ( 𝑋 ∈ 𝑉 → ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) ) |
2 |
|
rnss |
⊢ ( ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) ) |
3 |
1 2
|
syl |
⊢ ( 𝑋 ∈ 𝑉 → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) ) |
4 |
|
rnun |
⊢ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) = ( ran 𝑋 ∪ ran ( dom 𝑋 × ran 𝑋 ) ) |
5 |
|
rnxpss |
⊢ ran ( dom 𝑋 × ran 𝑋 ) ⊆ ran 𝑋 |
6 |
|
ssequn2 |
⊢ ( ran ( dom 𝑋 × ran 𝑋 ) ⊆ ran 𝑋 ↔ ( ran 𝑋 ∪ ran ( dom 𝑋 × ran 𝑋 ) ) = ran 𝑋 ) |
7 |
5 6
|
mpbi |
⊢ ( ran 𝑋 ∪ ran ( dom 𝑋 × ran 𝑋 ) ) = ran 𝑋 |
8 |
4 7
|
eqtri |
⊢ ran ( 𝑋 ∪ ( dom 𝑋 × ran 𝑋 ) ) = ran 𝑋 |
9 |
3 8
|
sseqtrdi |
⊢ ( 𝑋 ∈ 𝑉 → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ⊆ ran 𝑋 ) |
10 |
|
ssmin |
⊢ 𝑋 ⊆ ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } |
11 |
|
rnss |
⊢ ( 𝑋 ⊆ ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } → ran 𝑋 ⊆ ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ) |
12 |
10 11
|
mp1i |
⊢ ( 𝑋 ∈ 𝑉 → ran 𝑋 ⊆ ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } ) |
13 |
9 12
|
eqssd |
⊢ ( 𝑋 ∈ 𝑉 → ran ∩ { 𝑥 ∣ ( 𝑋 ⊆ 𝑥 ∧ ( 𝑥 ∘ 𝑥 ) ⊆ 𝑥 ) } = ran 𝑋 ) |