Metamath Proof Explorer


Theorem rspc2daf

Description: Double restricted specialization, using implicit substitution. (Contributed by Thierry Arnoux, 4-Jul-2023)

Ref Expression
Hypotheses sbc2iedf.1 ⊢ Ⅎ 𝑥 𝜑
sbc2iedf.2 ⊢ Ⅎ 𝑦 𝜑
sbc2iedf.3 ⊢ Ⅎ 𝑥 𝜒
sbc2iedf.4 ⊢ Ⅎ 𝑦 𝜒
sbc2iedf.5 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
sbc2iedf.6 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
sbc2iedf.7 ⊢ ( ( 𝜑 ∧ ( 𝑥 = 𝐴 ∧ 𝑦 = 𝐵 ) ) → ( 𝜓 ↔ 𝜒 ) )
rspc2daf.8 ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝑉 ∀ 𝑦 ∈ 𝑊 𝜓 )
Assertion rspc2daf ( 𝜑 → 𝜒 )

Proof

Step Hyp Ref Expression
1 sbc2iedf.1 ⊢ Ⅎ 𝑥 𝜑
2 sbc2iedf.2 ⊢ Ⅎ 𝑦 𝜑
3 sbc2iedf.3 ⊢ Ⅎ 𝑥 𝜒
4 sbc2iedf.4 ⊢ Ⅎ 𝑦 𝜒
5 sbc2iedf.5 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
6 sbc2iedf.6 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
7 sbc2iedf.7 ⊢ ( ( 𝜑 ∧ ( 𝑥 = 𝐴 ∧ 𝑦 = 𝐵 ) ) → ( 𝜓 ↔ 𝜒 ) )
8 rspc2daf.8 ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝑉 ∀ 𝑦 ∈ 𝑊 𝜓 )
9 nfcv ⊢ Ⅎ 𝑥 𝑊
10 nfsbc1v ⊢ Ⅎ 𝑥 [ 𝐴 / 𝑥 ] 𝜓
11 9 10 nfralw ⊢ Ⅎ 𝑥 ∀ 𝑦 ∈ 𝑊 [ 𝐴 / 𝑥 ] 𝜓
12 nfv ⊢ Ⅎ 𝑦 𝑥 = 𝐴
13 2 12 nfan ⊢ Ⅎ 𝑦 ( 𝜑 ∧ 𝑥 = 𝐴 )
14 sbceq1a ⊢ ( 𝑥 = 𝐴 → ( 𝜓 ↔ [ 𝐴 / 𝑥 ] 𝜓 ) )
15 14 adantl ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → ( 𝜓 ↔ [ 𝐴 / 𝑥 ] 𝜓 ) )
16 13 15 ralbid ⊢ ( ( 𝜑 ∧ 𝑥 = 𝐴 ) → ( ∀ 𝑦 ∈ 𝑊 𝜓 ↔ ∀ 𝑦 ∈ 𝑊 [ 𝐴 / 𝑥 ] 𝜓 ) )
17 1 11 5 16 rspcdf ⊢ ( 𝜑 → ( ∀ 𝑥 ∈ 𝑉 ∀ 𝑦 ∈ 𝑊 𝜓 → ∀ 𝑦 ∈ 𝑊 [ 𝐴 / 𝑥 ] 𝜓 ) )
18 8 17 mpd ⊢ ( 𝜑 → ∀ 𝑦 ∈ 𝑊 [ 𝐴 / 𝑥 ] 𝜓 )
19 nfsbc1v ⊢ Ⅎ 𝑦 [ 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜓
20 sbceq1a ⊢ ( 𝑦 = 𝐵 → ( [ 𝐴 / 𝑥 ] 𝜓 ↔ [ 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜓 ) )
21 20 adantl ⊢ ( ( 𝜑 ∧ 𝑦 = 𝐵 ) → ( [ 𝐴 / 𝑥 ] 𝜓 ↔ [ 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜓 ) )
22 2 19 6 21 rspcdf ⊢ ( 𝜑 → ( ∀ 𝑦 ∈ 𝑊 [ 𝐴 / 𝑥 ] 𝜓 → [ 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜓 ) )
23 18 22 mpd ⊢ ( 𝜑 → [ 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜓 )
24 1 2 3 4 5 6 7 sbc2iedf ⊢ ( 𝜑 → ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜓 ↔ 𝜒 ) )
25 sbccom ⊢ ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜓 ↔ [ 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜓 )
26 24 25 bitr3di ⊢ ( 𝜑 → ( 𝜒 ↔ [ 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜓 ) )
27 23 26 mpbird ⊢ ( 𝜑 → 𝜒 )