Metamath Proof Explorer


Theorem rspcedvdw

Description: Version of rspcedvd where the implicit substitution hypothesis does not have an antecedent, which also avoids a disjoint variable condition on ph , x . (Contributed by SN, 20-Aug-2024)

Ref Expression
Hypotheses rspcedvdw.s ⊢ ( 𝑥 = 𝐴 → ( 𝜓 ↔ 𝜒 ) )
rspcedvdw.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
rspcedvdw.2 ⊢ ( 𝜑 → 𝜒 )
Assertion rspcedvdw ( 𝜑 → ∃ 𝑥 ∈ 𝐵 𝜓 )

Proof

Step Hyp Ref Expression
1 rspcedvdw.s ⊢ ( 𝑥 = 𝐴 → ( 𝜓 ↔ 𝜒 ) )
2 rspcedvdw.1 ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
3 rspcedvdw.2 ⊢ ( 𝜑 → 𝜒 )
4 1 rspcev ⊢ ( ( 𝐴 ∈ 𝐵 ∧ 𝜒 ) → ∃ 𝑥 ∈ 𝐵 𝜓 )
5 2 3 4 syl2anc ⊢ ( 𝜑 → ∃ 𝑥 ∈ 𝐵 𝜓 )