Metamath Proof Explorer


Theorem salgenn0

Description: The set used in the definition of the generated sigma-algebra, is not empty. (Contributed by Glauco Siliprandi, 3-Jan-2021)

Ref Expression
Assertion salgenn0 ( 𝑋 ∈ 𝑉 → { 𝑠 ∈ SAlg ∣ ( ∪ 𝑠 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝑠 ) } ≠ ∅ )

Proof

Step Hyp Ref Expression
1 uniexg ⊢ ( 𝑋 ∈ 𝑉 → ∪ 𝑋 ∈ V )
2 pwsal ⊢ ( ∪ 𝑋 ∈ V → 𝒫 ∪ 𝑋 ∈ SAlg )
3 1 2 syl ⊢ ( 𝑋 ∈ 𝑉 → 𝒫 ∪ 𝑋 ∈ SAlg )
4 unipw ⊢ ∪ 𝒫 ∪ 𝑋 = ∪ 𝑋
5 4 a1i ⊢ ( 𝑋 ∈ 𝑉 → ∪ 𝒫 ∪ 𝑋 = ∪ 𝑋 )
6 pwuni ⊢ 𝑋 ⊆ 𝒫 ∪ 𝑋
7 6 a1i ⊢ ( 𝑋 ∈ 𝑉 → 𝑋 ⊆ 𝒫 ∪ 𝑋 )
8 5 7 jca ⊢ ( 𝑋 ∈ 𝑉 → ( ∪ 𝒫 ∪ 𝑋 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝒫 ∪ 𝑋 ) )
9 3 8 jca ⊢ ( 𝑋 ∈ 𝑉 → ( 𝒫 ∪ 𝑋 ∈ SAlg ∧ ( ∪ 𝒫 ∪ 𝑋 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝒫 ∪ 𝑋 ) ) )
10 unieq ⊢ ( 𝑠 = 𝒫 ∪ 𝑋 → ∪ 𝑠 = ∪ 𝒫 ∪ 𝑋 )
11 10 eqeq1d ⊢ ( 𝑠 = 𝒫 ∪ 𝑋 → ( ∪ 𝑠 = ∪ 𝑋 ↔ ∪ 𝒫 ∪ 𝑋 = ∪ 𝑋 ) )
12 sseq2 ⊢ ( 𝑠 = 𝒫 ∪ 𝑋 → ( 𝑋 ⊆ 𝑠 ↔ 𝑋 ⊆ 𝒫 ∪ 𝑋 ) )
13 11 12 anbi12d ⊢ ( 𝑠 = 𝒫 ∪ 𝑋 → ( ( ∪ 𝑠 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝑠 ) ↔ ( ∪ 𝒫 ∪ 𝑋 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝒫 ∪ 𝑋 ) ) )
14 13 elrab ⊢ ( 𝒫 ∪ 𝑋 ∈ { 𝑠 ∈ SAlg ∣ ( ∪ 𝑠 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝑠 ) } ↔ ( 𝒫 ∪ 𝑋 ∈ SAlg ∧ ( ∪ 𝒫 ∪ 𝑋 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝒫 ∪ 𝑋 ) ) )
15 9 14 sylibr ⊢ ( 𝑋 ∈ 𝑉 → 𝒫 ∪ 𝑋 ∈ { 𝑠 ∈ SAlg ∣ ( ∪ 𝑠 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝑠 ) } )
16 15 ne0d ⊢ ( 𝑋 ∈ 𝑉 → { 𝑠 ∈ SAlg ∣ ( ∪ 𝑠 = ∪ 𝑋 ∧ 𝑋 ⊆ 𝑠 ) } ≠ ∅ )