Metamath Proof Explorer


Theorem sbccom2

Description: Commutative law for double class substitution. (Contributed by Giovanni Mascellani, 31-May-2019)

Ref Expression
Hypothesis sbccom2.1 𝐴 ∈ V
Assertion sbccom2 ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 sbccom2.1 𝐴 ∈ V
2 sbcco ( [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐵 / 𝑦 ] 𝜑 )
3 2 bicomi ( [ 𝐵 / 𝑦 ] 𝜑[ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑 )
4 3 sbcbii ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 ] [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑 )
5 sbcco ( [ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 ] [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 ] [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑 )
6 5 bicomi ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 ] [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑 )
7 vex 𝑧 ∈ V
8 7 sbccom2lem ( [ 𝑧 / 𝑥 ] [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝑧 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
9 8 sbcbii ( [ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 ] [ 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝑧 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
10 4 6 9 3bitri ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜑[ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝑧 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
11 1 sbccom2lem ( [ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝑧 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
12 sbcco ( [ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
13 12 sbcbii ( [ 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑧 ] [ 𝑧 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
14 10 11 13 3bitri ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜑[ 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
15 csbco 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐵
16 dfsbcq ( 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 = 𝐴 / 𝑥 𝐵 → ( [ 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 ) )
17 15 16 ax-mp ( [ 𝐴 / 𝑧 𝑧 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
18 14 17 bitri ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑 )
19 sbccom ( [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝑤 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜑 )
20 19 sbcbii ( [ 𝐴 / 𝑥 𝐵 / 𝑤 ] [ 𝐴 / 𝑥 ] [ 𝑤 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜑 )
21 sbcco ( [ 𝐴 / 𝑥 𝐵 / 𝑤 ] [ 𝑤 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜑[ 𝐴 / 𝑥 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜑 )
22 18 20 21 3bitri ( [ 𝐴 / 𝑥 ] [ 𝐵 / 𝑦 ] 𝜑[ 𝐴 / 𝑥 𝐵 / 𝑦 ] [ 𝐴 / 𝑥 ] 𝜑 )