Metamath Proof Explorer


Theorem sgrp2nmndlem3

Description: Lemma 3 for sgrp2nmnd . (Contributed by AV, 29-Jan-2020)

Ref Expression
Hypotheses mgm2nsgrp.s ⊢ 𝑆 = { 𝐴 , 𝐵 }
mgm2nsgrp.b ⊢ ( Base ‘ 𝑀 ) = 𝑆
sgrp2nmnd.o ⊢ ( +g ‘ 𝑀 ) = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝐴 , 𝐴 , 𝐵 ) )
sgrp2nmnd.p ⊢ ⚬ = ( +g ‘ 𝑀 )
Assertion sgrp2nmndlem3 ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) → ( 𝐵 ⚬ 𝐶 ) = 𝐵 )

Proof

Step Hyp Ref Expression
1 mgm2nsgrp.s ⊢ 𝑆 = { 𝐴 , 𝐵 }
2 mgm2nsgrp.b ⊢ ( Base ‘ 𝑀 ) = 𝑆
3 sgrp2nmnd.o ⊢ ( +g ‘ 𝑀 ) = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝐴 , 𝐴 , 𝐵 ) )
4 sgrp2nmnd.p ⊢ ⚬ = ( +g ‘ 𝑀 )
5 4 3 eqtri ⊢ ⚬ = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝐴 , 𝐴 , 𝐵 ) )
6 5 a1i ⊢ ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) → ⚬ = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝐴 , 𝐴 , 𝐵 ) ) )
7 df-ne ⊢ ( 𝐴 ≠ 𝐵 ↔ ¬ 𝐴 = 𝐵 )
8 eqeq2 ⊢ ( 𝑥 = 𝐵 → ( 𝐴 = 𝑥 ↔ 𝐴 = 𝐵 ) )
9 8 adantr ⊢ ( ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) → ( 𝐴 = 𝑥 ↔ 𝐴 = 𝐵 ) )
10 eqcom ⊢ ( 𝐴 = 𝑥 ↔ 𝑥 = 𝐴 )
11 9 10 bitr3di ⊢ ( ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) → ( 𝐴 = 𝐵 ↔ 𝑥 = 𝐴 ) )
12 11 notbid ⊢ ( ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) → ( ¬ 𝐴 = 𝐵 ↔ ¬ 𝑥 = 𝐴 ) )
13 12 biimpcd ⊢ ( ¬ 𝐴 = 𝐵 → ( ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) → ¬ 𝑥 = 𝐴 ) )
14 7 13 sylbi ⊢ ( 𝐴 ≠ 𝐵 → ( ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) → ¬ 𝑥 = 𝐴 ) )
15 14 3ad2ant3 ⊢ ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) → ( ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) → ¬ 𝑥 = 𝐴 ) )
16 15 imp ⊢ ( ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) ∧ ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) ) → ¬ 𝑥 = 𝐴 )
17 16 iffalsed ⊢ ( ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) ∧ ( 𝑥 = 𝐵 ∧ 𝑦 = 𝐶 ) ) → if ( 𝑥 = 𝐴 , 𝐴 , 𝐵 ) = 𝐵 )
18 simp2 ⊢ ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) → 𝐵 ∈ 𝑆 )
19 simp1 ⊢ ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) → 𝐶 ∈ 𝑆 )
20 6 17 18 19 18 ovmpod ⊢ ( ( 𝐶 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ∧ 𝐴 ≠ 𝐵 ) → ( 𝐵 ⚬ 𝐶 ) = 𝐵 )