Metamath Proof Explorer


Theorem sltsdisj

Description: If A preceeds B , then A and B are disjoint. (Contributed by Scott Fenton, 18-Sep-2024)

Ref Expression
Assertion sltsdisj ( 𝐴 <<s 𝐵 → ( 𝐴 ∩ 𝐵 ) = ∅ )

Proof

Step Hyp Ref Expression
1 sltsss1 ⊢ ( 𝐴 <<s 𝐵 → 𝐴 ⊆ No )
2 1 sselda ⊢ ( ( 𝐴 <<s 𝐵 ∧ 𝑥 ∈ 𝐴 ) → 𝑥 ∈ No )
3 ltsirr ⊢ ( 𝑥 ∈ No → ¬ 𝑥 <s 𝑥 )
4 2 3 syl ⊢ ( ( 𝐴 <<s 𝐵 ∧ 𝑥 ∈ 𝐴 ) → ¬ 𝑥 <s 𝑥 )
5 sltssepc ⊢ ( ( 𝐴 <<s 𝐵 ∧ 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ 𝐵 ) → 𝑥 <s 𝑥 )
6 5 3expa ⊢ ( ( ( 𝐴 <<s 𝐵 ∧ 𝑥 ∈ 𝐴 ) ∧ 𝑥 ∈ 𝐵 ) → 𝑥 <s 𝑥 )
7 4 6 mtand ⊢ ( ( 𝐴 <<s 𝐵 ∧ 𝑥 ∈ 𝐴 ) → ¬ 𝑥 ∈ 𝐵 )
8 7 ralrimiva ⊢ ( 𝐴 <<s 𝐵 → ∀ 𝑥 ∈ 𝐴 ¬ 𝑥 ∈ 𝐵 )
9 disj ⊢ ( ( 𝐴 ∩ 𝐵 ) = ∅ ↔ ∀ 𝑥 ∈ 𝐴 ¬ 𝑥 ∈ 𝐵 )
10 8 9 sylibr ⊢ ( 𝐴 <<s 𝐵 → ( 𝐴 ∩ 𝐵 ) = ∅ )