Metamath Proof Explorer


Theorem stm1addi

Description: Sum of states whose meet is 1. (Contributed by NM, 11-Nov-1999) (New usage is discouraged.)

Ref Expression
Hypotheses stle.1 ⊢ 𝐴 ∈ Cℋ
stle.2 ⊢ 𝐵 ∈ Cℋ
Assertion stm1addi ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( 𝐴 ∩ 𝐵 ) ) = 1 → ( ( 𝑆 ‘ 𝐴 ) + ( 𝑆 ‘ 𝐵 ) ) = 2 ) )

Proof

Step Hyp Ref Expression
1 stle.1 ⊢ 𝐴 ∈ Cℋ
2 stle.2 ⊢ 𝐵 ∈ Cℋ
3 1 2 stm1i ⊢ ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( 𝐴 ∩ 𝐵 ) ) = 1 → ( 𝑆 ‘ 𝐴 ) = 1 ) )
4 1 2 stm1ri ⊢ ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( 𝐴 ∩ 𝐵 ) ) = 1 → ( 𝑆 ‘ 𝐵 ) = 1 ) )
5 3 4 jcad ⊢ ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( 𝐴 ∩ 𝐵 ) ) = 1 → ( ( 𝑆 ‘ 𝐴 ) = 1 ∧ ( 𝑆 ‘ 𝐵 ) = 1 ) ) )
6 oveq12 ⊢ ( ( ( 𝑆 ‘ 𝐴 ) = 1 ∧ ( 𝑆 ‘ 𝐵 ) = 1 ) → ( ( 𝑆 ‘ 𝐴 ) + ( 𝑆 ‘ 𝐵 ) ) = ( 1 + 1 ) )
7 df-2 ⊢ 2 = ( 1 + 1 )
8 6 7 eqtr4di ⊢ ( ( ( 𝑆 ‘ 𝐴 ) = 1 ∧ ( 𝑆 ‘ 𝐵 ) = 1 ) → ( ( 𝑆 ‘ 𝐴 ) + ( 𝑆 ‘ 𝐵 ) ) = 2 )
9 5 8 syl6 ⊢ ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( 𝐴 ∩ 𝐵 ) ) = 1 → ( ( 𝑆 ‘ 𝐴 ) + ( 𝑆 ‘ 𝐵 ) ) = 2 ) )