Metamath Proof Explorer


Theorem tanhcl

Description: The closure of the tanh function with complex argument. (Contributed by Jon Pennant, 9-Sep-2026)

Ref Expression
Assertion tanhcl ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( tanh ‘ 𝐴 ) ∈ ℂ )

Proof

Step Hyp Ref Expression
1 coshcl ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ 𝐴 ) ∈ ℂ )
2 1 adantr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( cosh ‘ 𝐴 ) ∈ ℂ )
3 simpr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( cosh ‘ 𝐴 ) ≠ 0 )
4 2 3 eldifsnd ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( cosh ‘ 𝐴 ) ∈ ( ℂ ∖ { 0 } ) )
5 coshf ⊢ cosh : ℂ ⟶ ℂ
6 ffn ⊢ ( cosh : ℂ ⟶ ℂ → cosh Fn ℂ )
7 elpreima ⊢ ( cosh Fn ℂ → ( 𝐴 ∈ ( ◡ cosh “ ( ℂ ∖ { 0 } ) ) ↔ ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ∈ ( ℂ ∖ { 0 } ) ) ) )
8 5 6 7 mp2b ⊢ ( 𝐴 ∈ ( ◡ cosh “ ( ℂ ∖ { 0 } ) ) ↔ ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ∈ ( ℂ ∖ { 0 } ) ) )
9 tanhf ⊢ tanh : ( ◡ cosh “ ( ℂ ∖ { 0 } ) ) ⟶ ℂ
10 9 ffvelcdmi ⊢ ( 𝐴 ∈ ( ◡ cosh “ ( ℂ ∖ { 0 } ) ) → ( tanh ‘ 𝐴 ) ∈ ℂ )
11 8 10 sylbir ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ∈ ( ℂ ∖ { 0 } ) ) → ( tanh ‘ 𝐴 ) ∈ ℂ )
12 4 11 syldan ⊢ ( ( 𝐴 ∈ ℂ ∧ ( cosh ‘ 𝐴 ) ≠ 0 ) → ( tanh ‘ 𝐴 ) ∈ ℂ )