Metamath Proof Explorer


Theorem uneqdifeq

Description: Two ways to say that A and B partition C (when A and B don't overlap and A is a part of C ). (Contributed by FL, 17-Nov-2008) (Proof shortened by JJ, 14-Jul-2021)

Ref Expression
Assertion uneqdifeq ( ( 𝐴𝐶 ∧ ( 𝐴𝐵 ) = ∅ ) → ( ( 𝐴𝐵 ) = 𝐶 ↔ ( 𝐶𝐴 ) = 𝐵 ) )

Proof

Step Hyp Ref Expression
1 uncom ( 𝐵𝐴 ) = ( 𝐴𝐵 )
2 eqtr ( ( ( 𝐵𝐴 ) = ( 𝐴𝐵 ) ∧ ( 𝐴𝐵 ) = 𝐶 ) → ( 𝐵𝐴 ) = 𝐶 )
3 2 eqcomd ( ( ( 𝐵𝐴 ) = ( 𝐴𝐵 ) ∧ ( 𝐴𝐵 ) = 𝐶 ) → 𝐶 = ( 𝐵𝐴 ) )
4 difeq1 ( 𝐶 = ( 𝐵𝐴 ) → ( 𝐶𝐴 ) = ( ( 𝐵𝐴 ) ∖ 𝐴 ) )
5 difun2 ( ( 𝐵𝐴 ) ∖ 𝐴 ) = ( 𝐵𝐴 )
6 eqtr ( ( ( 𝐶𝐴 ) = ( ( 𝐵𝐴 ) ∖ 𝐴 ) ∧ ( ( 𝐵𝐴 ) ∖ 𝐴 ) = ( 𝐵𝐴 ) ) → ( 𝐶𝐴 ) = ( 𝐵𝐴 ) )
7 ineqcom ( ( 𝐴𝐵 ) = ∅ ↔ ( 𝐵𝐴 ) = ∅ )
8 disj3 ( ( 𝐵𝐴 ) = ∅ ↔ 𝐵 = ( 𝐵𝐴 ) )
9 7 8 bitri ( ( 𝐴𝐵 ) = ∅ ↔ 𝐵 = ( 𝐵𝐴 ) )
10 eqtr ( ( ( 𝐶𝐴 ) = ( 𝐵𝐴 ) ∧ ( 𝐵𝐴 ) = 𝐵 ) → ( 𝐶𝐴 ) = 𝐵 )
11 10 expcom ( ( 𝐵𝐴 ) = 𝐵 → ( ( 𝐶𝐴 ) = ( 𝐵𝐴 ) → ( 𝐶𝐴 ) = 𝐵 ) )
12 11 eqcoms ( 𝐵 = ( 𝐵𝐴 ) → ( ( 𝐶𝐴 ) = ( 𝐵𝐴 ) → ( 𝐶𝐴 ) = 𝐵 ) )
13 9 12 sylbi ( ( 𝐴𝐵 ) = ∅ → ( ( 𝐶𝐴 ) = ( 𝐵𝐴 ) → ( 𝐶𝐴 ) = 𝐵 ) )
14 6 13 syl5com ( ( ( 𝐶𝐴 ) = ( ( 𝐵𝐴 ) ∖ 𝐴 ) ∧ ( ( 𝐵𝐴 ) ∖ 𝐴 ) = ( 𝐵𝐴 ) ) → ( ( 𝐴𝐵 ) = ∅ → ( 𝐶𝐴 ) = 𝐵 ) )
15 4 5 14 sylancl ( 𝐶 = ( 𝐵𝐴 ) → ( ( 𝐴𝐵 ) = ∅ → ( 𝐶𝐴 ) = 𝐵 ) )
16 3 15 syl ( ( ( 𝐵𝐴 ) = ( 𝐴𝐵 ) ∧ ( 𝐴𝐵 ) = 𝐶 ) → ( ( 𝐴𝐵 ) = ∅ → ( 𝐶𝐴 ) = 𝐵 ) )
17 1 16 mpan ( ( 𝐴𝐵 ) = 𝐶 → ( ( 𝐴𝐵 ) = ∅ → ( 𝐶𝐴 ) = 𝐵 ) )
18 17 com12 ( ( 𝐴𝐵 ) = ∅ → ( ( 𝐴𝐵 ) = 𝐶 → ( 𝐶𝐴 ) = 𝐵 ) )
19 18 adantl ( ( 𝐴𝐶 ∧ ( 𝐴𝐵 ) = ∅ ) → ( ( 𝐴𝐵 ) = 𝐶 → ( 𝐶𝐴 ) = 𝐵 ) )
20 simpl ( ( 𝐴𝐶 ∧ ( 𝐶𝐴 ) = 𝐵 ) → 𝐴𝐶 )
21 difssd ( ( 𝐶𝐴 ) = 𝐵 → ( 𝐶𝐴 ) ⊆ 𝐶 )
22 sseq1 ( ( 𝐶𝐴 ) = 𝐵 → ( ( 𝐶𝐴 ) ⊆ 𝐶𝐵𝐶 ) )
23 21 22 mpbid ( ( 𝐶𝐴 ) = 𝐵𝐵𝐶 )
24 23 adantl ( ( 𝐴𝐶 ∧ ( 𝐶𝐴 ) = 𝐵 ) → 𝐵𝐶 )
25 20 24 unssd ( ( 𝐴𝐶 ∧ ( 𝐶𝐴 ) = 𝐵 ) → ( 𝐴𝐵 ) ⊆ 𝐶 )
26 eqimss ( ( 𝐶𝐴 ) = 𝐵 → ( 𝐶𝐴 ) ⊆ 𝐵 )
27 ssundif ( 𝐶 ⊆ ( 𝐴𝐵 ) ↔ ( 𝐶𝐴 ) ⊆ 𝐵 )
28 26 27 sylibr ( ( 𝐶𝐴 ) = 𝐵𝐶 ⊆ ( 𝐴𝐵 ) )
29 28 adantl ( ( 𝐴𝐶 ∧ ( 𝐶𝐴 ) = 𝐵 ) → 𝐶 ⊆ ( 𝐴𝐵 ) )
30 25 29 eqssd ( ( 𝐴𝐶 ∧ ( 𝐶𝐴 ) = 𝐵 ) → ( 𝐴𝐵 ) = 𝐶 )
31 30 ex ( 𝐴𝐶 → ( ( 𝐶𝐴 ) = 𝐵 → ( 𝐴𝐵 ) = 𝐶 ) )
32 31 adantr ( ( 𝐴𝐶 ∧ ( 𝐴𝐵 ) = ∅ ) → ( ( 𝐶𝐴 ) = 𝐵 → ( 𝐴𝐵 ) = 𝐶 ) )
33 19 32 impbid ( ( 𝐴𝐶 ∧ ( 𝐴𝐵 ) = ∅ ) → ( ( 𝐴𝐵 ) = 𝐶 ↔ ( 𝐶𝐴 ) = 𝐵 ) )