Metamath Proof Explorer


Theorem uniimafveqt

Description: The union of the image of a subset S of the domain of a function with elements having the same function value is the function value at one of the elements of S . (Contributed by AV, 5-Mar-2024)

Ref Expression
Assertion uniimafveqt ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) → ( ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) → ∪ ( 𝐹 “ 𝑆 ) = ( 𝐹 ‘ 𝑋 ) ) )

Proof

Step Hyp Ref Expression
1 ffun ⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 → Fun 𝐹 )
2 1 3ad2ant1 ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) → Fun 𝐹 )
3 2 adantr ⊢ ( ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) ∧ ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) ) → Fun 𝐹 )
4 funiunfv ⊢ ( Fun 𝐹 → ∪ 𝑦 ∈ 𝑆 ( 𝐹 ‘ 𝑦 ) = ∪ ( 𝐹 “ 𝑆 ) )
5 3 4 syl ⊢ ( ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) ∧ ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) ) → ∪ 𝑦 ∈ 𝑆 ( 𝐹 ‘ 𝑦 ) = ∪ ( 𝐹 “ 𝑆 ) )
6 simp3 ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) → 𝑋 ∈ 𝑆 )
7 fveqeq2 ⊢ ( 𝑥 = 𝑦 → ( ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) ↔ ( 𝐹 ‘ 𝑦 ) = ( 𝐹 ‘ 𝑋 ) ) )
8 7 cbvralvw ⊢ ( ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) ↔ ∀ 𝑦 ∈ 𝑆 ( 𝐹 ‘ 𝑦 ) = ( 𝐹 ‘ 𝑋 ) )
9 8 biimpi ⊢ ( ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) → ∀ 𝑦 ∈ 𝑆 ( 𝐹 ‘ 𝑦 ) = ( 𝐹 ‘ 𝑋 ) )
10 fveq2 ⊢ ( 𝑦 = 𝑋 → ( 𝐹 ‘ 𝑦 ) = ( 𝐹 ‘ 𝑋 ) )
11 10 iuneqconst ⊢ ( ( 𝑋 ∈ 𝑆 ∧ ∀ 𝑦 ∈ 𝑆 ( 𝐹 ‘ 𝑦 ) = ( 𝐹 ‘ 𝑋 ) ) → ∪ 𝑦 ∈ 𝑆 ( 𝐹 ‘ 𝑦 ) = ( 𝐹 ‘ 𝑋 ) )
12 6 9 11 syl2an ⊢ ( ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) ∧ ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) ) → ∪ 𝑦 ∈ 𝑆 ( 𝐹 ‘ 𝑦 ) = ( 𝐹 ‘ 𝑋 ) )
13 5 12 eqtr3d ⊢ ( ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) ∧ ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) ) → ∪ ( 𝐹 “ 𝑆 ) = ( 𝐹 ‘ 𝑋 ) )
14 13 ex ⊢ ( ( 𝐹 : 𝐴 ⟶ 𝐵 ∧ 𝑆 ⊆ 𝐴 ∧ 𝑋 ∈ 𝑆 ) → ( ∀ 𝑥 ∈ 𝑆 ( 𝐹 ‘ 𝑥 ) = ( 𝐹 ‘ 𝑋 ) → ∪ ( 𝐹 “ 𝑆 ) = ( 𝐹 ‘ 𝑋 ) ) )