Metamath Proof Explorer


Theorem vsetrec

Description: Construct _V using set recursion. The proof indirectly uses trcl , which relies on rec , but theoretically C in trcl could be constructed using setrecs instead. The proof of this theorem uses the dummy variable a rather than x to avoid a distinct variable requirement between F and x . (Contributed by Emmett Weisz, 23-Jun-2021)

Ref Expression
Hypothesis vsetrec.1 ⊢ 𝐹 = ( 𝑥 ∈ V ↦ 𝒫 𝑥 )
Assertion vsetrec setrecs ( 𝐹 ) = V

Proof

Step Hyp Ref Expression
1 vsetrec.1 ⊢ 𝐹 = ( 𝑥 ∈ V ↦ 𝒫 𝑥 )
2 setind ⊢ ( ∀ 𝑎 ( 𝑎 ⊆ setrecs ( 𝐹 ) → 𝑎 ∈ setrecs ( 𝐹 ) ) → setrecs ( 𝐹 ) = V )
3 vex ⊢ 𝑎 ∈ V
4 3 pwid ⊢ 𝑎 ∈ 𝒫 𝑎
5 pweq ⊢ ( 𝑥 = 𝑎 → 𝒫 𝑥 = 𝒫 𝑎 )
6 vpwex ⊢ 𝒫 𝑎 ∈ V
7 5 1 6 fvmpt ⊢ ( 𝑎 ∈ V → ( 𝐹 ‘ 𝑎 ) = 𝒫 𝑎 )
8 3 7 ax-mp ⊢ ( 𝐹 ‘ 𝑎 ) = 𝒫 𝑎
9 eqid ⊢ setrecs ( 𝐹 ) = setrecs ( 𝐹 )
10 3 a1i ⊢ ( 𝑎 ⊆ setrecs ( 𝐹 ) → 𝑎 ∈ V )
11 id ⊢ ( 𝑎 ⊆ setrecs ( 𝐹 ) → 𝑎 ⊆ setrecs ( 𝐹 ) )
12 9 10 11 setrec1 ⊢ ( 𝑎 ⊆ setrecs ( 𝐹 ) → ( 𝐹 ‘ 𝑎 ) ⊆ setrecs ( 𝐹 ) )
13 8 12 eqsstrrid ⊢ ( 𝑎 ⊆ setrecs ( 𝐹 ) → 𝒫 𝑎 ⊆ setrecs ( 𝐹 ) )
14 13 sseld ⊢ ( 𝑎 ⊆ setrecs ( 𝐹 ) → ( 𝑎 ∈ 𝒫 𝑎 → 𝑎 ∈ setrecs ( 𝐹 ) ) )
15 4 14 mpi ⊢ ( 𝑎 ⊆ setrecs ( 𝐹 ) → 𝑎 ∈ setrecs ( 𝐹 ) )
16 2 15 mpg ⊢ setrecs ( 𝐹 ) = V