Metamath Proof Explorer


Theorem wl-ifpimpr

Description: If one case of an if- condition is a consequence of the other, the expression in df-ifp can be shortened. (Contributed by Wolf Lammen, 12-Jun-2024)

Ref Expression
Assertion wl-ifpimpr ( ( 𝜒 → 𝜓 ) → ( if- ( 𝜑 , 𝜓 , 𝜒 ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∨ 𝜒 ) ) )

Proof

Step Hyp Ref Expression
1 pm4.72 ⊢ ( ( 𝜒 → 𝜓 ) ↔ ( 𝜓 ↔ ( 𝜒 ∨ 𝜓 ) ) )
2 1 biimpi ⊢ ( ( 𝜒 → 𝜓 ) → ( 𝜓 ↔ ( 𝜒 ∨ 𝜓 ) ) )
3 orcom ⊢ ( ( 𝜒 ∨ 𝜓 ) ↔ ( 𝜓 ∨ 𝜒 ) )
4 2 3 bitrdi ⊢ ( ( 𝜒 → 𝜓 ) → ( 𝜓 ↔ ( 𝜓 ∨ 𝜒 ) ) )
5 4 anbi2d ⊢ ( ( 𝜒 → 𝜓 ) → ( ( 𝜑 ∧ 𝜓 ) ↔ ( 𝜑 ∧ ( 𝜓 ∨ 𝜒 ) ) ) )
6 andi ⊢ ( ( 𝜑 ∧ ( 𝜓 ∨ 𝜒 ) ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∨ ( 𝜑 ∧ 𝜒 ) ) )
7 5 6 bitrdi ⊢ ( ( 𝜒 → 𝜓 ) → ( ( 𝜑 ∧ 𝜓 ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∨ ( 𝜑 ∧ 𝜒 ) ) ) )
8 7 orbi1d ⊢ ( ( 𝜒 → 𝜓 ) → ( ( ( 𝜑 ∧ 𝜓 ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) ↔ ( ( ( 𝜑 ∧ 𝜓 ) ∨ ( 𝜑 ∧ 𝜒 ) ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) ) )
9 df-ifp ⊢ ( if- ( 𝜑 , 𝜓 , 𝜒 ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) )
10 biidd ⊢ ( 𝜑 → ( 𝜒 ↔ 𝜒 ) )
11 biidd ⊢ ( ¬ 𝜑 → ( 𝜒 ↔ 𝜒 ) )
12 10 11 cases ⊢ ( 𝜒 ↔ ( ( 𝜑 ∧ 𝜒 ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) )
13 12 orbi2i ⊢ ( ( ( 𝜑 ∧ 𝜓 ) ∨ 𝜒 ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∨ ( ( 𝜑 ∧ 𝜒 ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) ) )
14 orass ⊢ ( ( ( ( 𝜑 ∧ 𝜓 ) ∨ ( 𝜑 ∧ 𝜒 ) ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∨ ( ( 𝜑 ∧ 𝜒 ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) ) )
15 13 14 bitr4i ⊢ ( ( ( 𝜑 ∧ 𝜓 ) ∨ 𝜒 ) ↔ ( ( ( 𝜑 ∧ 𝜓 ) ∨ ( 𝜑 ∧ 𝜒 ) ) ∨ ( ¬ 𝜑 ∧ 𝜒 ) ) )
16 8 9 15 3bitr4g ⊢ ( ( 𝜒 → 𝜓 ) → ( if- ( 𝜑 , 𝜓 , 𝜒 ) ↔ ( ( 𝜑 ∧ 𝜓 ) ∨ 𝜒 ) ) )