Metamath Proof Explorer


Theorem 2arwcatlem1

Description: Lemma for 2arwcat . (Contributed by Zhi Wang, 5-Nov-2025)

Ref Expression
Hypothesis 2arwcatlem1.x ⊢ X H X = 0 ˙ 1 ˙
Assertion 2arwcatlem1 ⊢ x = X ∧ y = X ∧ z = X ∧ w = X ∧ f = 0 ˙ ∨ f = 1 ˙ ∧ g = 0 ˙ ∨ g = 1 ˙ ∧ k = 0 ˙ ∨ k = 1 ˙ ↔ x ∈ X ∧ y ∈ X ∧ z ∈ X ∧ w ∈ X ∧ f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w

Proof

Step Hyp Ref Expression
1 2arwcatlem1.x ⊢ X H X = 0 ˙ 1 ˙
2 df-3an ⊢ x ∈ X ∧ y ∈ X ∧ z ∈ X ∧ w ∈ X ∧ f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w ↔ x ∈ X ∧ y ∈ X ∧ z ∈ X ∧ w ∈ X ∧ f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w
3 velsn ⊢ x ∈ X ↔ x = X
4 velsn ⊢ y ∈ X ↔ y = X
5 3 4 anbi12i ⊢ x ∈ X ∧ y ∈ X ↔ x = X ∧ y = X
6 velsn ⊢ z ∈ X ↔ z = X
7 velsn ⊢ w ∈ X ↔ w = X
8 6 7 anbi12i ⊢ z ∈ X ∧ w ∈ X ↔ z = X ∧ w = X
9 5 8 anbi12i ⊢ x ∈ X ∧ y ∈ X ∧ z ∈ X ∧ w ∈ X ↔ x = X ∧ y = X ∧ z = X ∧ w = X
10 9 anbi1i ⊢ x ∈ X ∧ y ∈ X ∧ z ∈ X ∧ w ∈ X ∧ f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w ↔ x = X ∧ y = X ∧ z = X ∧ w = X ∧ f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w
11 simpll ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → x = X
12 simplr ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → y = X
13 11 12 oveq12d ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → x H y = X H X
14 13 1 eqtrdi ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → x H y = 0 ˙ 1 ˙
15 14 eleq2d ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → f ∈ x H y ↔ f ∈ 0 ˙ 1 ˙
16 simprl ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → z = X
17 12 16 oveq12d ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → y H z = X H X
18 17 1 eqtrdi ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → y H z = 0 ˙ 1 ˙
19 18 eleq2d ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → g ∈ y H z ↔ g ∈ 0 ˙ 1 ˙
20 simprr ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → w = X
21 16 20 oveq12d ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → z H w = X H X
22 21 1 eqtrdi ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → z H w = 0 ˙ 1 ˙
23 22 eleq2d ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → k ∈ z H w ↔ k ∈ 0 ˙ 1 ˙
24 15 19 23 3anbi123d ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w ↔ f ∈ 0 ˙ 1 ˙ ∧ g ∈ 0 ˙ 1 ˙ ∧ k ∈ 0 ˙ 1 ˙
25 vex ⊢ f ∈ V
26 25 elpr ⊢ f ∈ 0 ˙ 1 ˙ ↔ f = 0 ˙ ∨ f = 1 ˙
27 vex ⊢ g ∈ V
28 27 elpr ⊢ g ∈ 0 ˙ 1 ˙ ↔ g = 0 ˙ ∨ g = 1 ˙
29 vex ⊢ k ∈ V
30 29 elpr ⊢ k ∈ 0 ˙ 1 ˙ ↔ k = 0 ˙ ∨ k = 1 ˙
31 26 28 30 3anbi123i ⊢ f ∈ 0 ˙ 1 ˙ ∧ g ∈ 0 ˙ 1 ˙ ∧ k ∈ 0 ˙ 1 ˙ ↔ f = 0 ˙ ∨ f = 1 ˙ ∧ g = 0 ˙ ∨ g = 1 ˙ ∧ k = 0 ˙ ∨ k = 1 ˙
32 24 31 bitrdi ⊢ x = X ∧ y = X ∧ z = X ∧ w = X → f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w ↔ f = 0 ˙ ∨ f = 1 ˙ ∧ g = 0 ˙ ∨ g = 1 ˙ ∧ k = 0 ˙ ∨ k = 1 ˙
33 32 pm5.32i ⊢ x = X ∧ y = X ∧ z = X ∧ w = X ∧ f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w ↔ x = X ∧ y = X ∧ z = X ∧ w = X ∧ f = 0 ˙ ∨ f = 1 ˙ ∧ g = 0 ˙ ∨ g = 1 ˙ ∧ k = 0 ˙ ∨ k = 1 ˙
34 2 10 33 3bitrri ⊢ x = X ∧ y = X ∧ z = X ∧ w = X ∧ f = 0 ˙ ∨ f = 1 ˙ ∧ g = 0 ˙ ∨ g = 1 ˙ ∧ k = 0 ˙ ∨ k = 1 ˙ ↔ x ∈ X ∧ y ∈ X ∧ z ∈ X ∧ w ∈ X ∧ f ∈ x H y ∧ g ∈ y H z ∧ k ∈ z H w