Metamath Proof Explorer


Theorem 2rspcedvdw

Description: Double application of rspcedvdw . (Contributed by SN, 24-Aug-2024)

Ref Expression
Hypotheses 2rspcedvdw.1 ⊢ x = A → ψ ↔ χ
2rspcedvdw.2 ⊢ y = B → χ ↔ θ
2rspcedvdw.a ⊢ φ → A ∈ X
2rspcedvdw.b ⊢ φ → B ∈ Y
2rspcedvdw.3 ⊢ φ → θ
Assertion 2rspcedvdw ⊢ φ → ∃ x ∈ X ∃ y ∈ Y ψ

Proof

Step Hyp Ref Expression
1 2rspcedvdw.1 ⊢ x = A → ψ ↔ χ
2 2rspcedvdw.2 ⊢ y = B → χ ↔ θ
3 2rspcedvdw.a ⊢ φ → A ∈ X
4 2rspcedvdw.b ⊢ φ → B ∈ Y
5 2rspcedvdw.3 ⊢ φ → θ
6 1 2 rspc2ev ⊢ A ∈ X ∧ B ∈ Y ∧ θ → ∃ x ∈ X ∃ y ∈ Y ψ
7 3 4 5 6 syl3anc ⊢ φ → ∃ x ∈ X ∃ y ∈ Y ψ