Metamath Proof Explorer


Theorem 2zrng0

Description: The additive identity of R is the complex number 0. (Contributed by AV, 11-Feb-2020)

Ref Expression
Hypotheses 2zrng.e ⊢ E = z ∈ ℤ | ∃ x ∈ ℤ z = 2 ⁢ x
2zrngbas.r ⊢ R = ℂ fld ↾ 𝑠 E
Assertion 2zrng0 ⊢ 0 = 0 R

Proof

Step Hyp Ref Expression
1 2zrng.e ⊢ E = z ∈ ℤ | ∃ x ∈ ℤ z = 2 ⁢ x
2 2zrngbas.r ⊢ R = ℂ fld ↾ 𝑠 E
3 cncrng ⊢ ℂ fld ∈ CRing
4 crngring ⊢ ℂ fld ∈ CRing → ℂ fld ∈ Ring
5 ringmnd ⊢ ℂ fld ∈ Ring → ℂ fld ∈ Mnd
6 3 4 5 mp2b ⊢ ℂ fld ∈ Mnd
7 1 0even ⊢ 0 ∈ E
8 ssrab2 ⊢ z ∈ ℤ | ∃ x ∈ ℤ z = 2 ⁢ x ⊆ ℤ
9 1 8 eqsstri ⊢ E ⊆ ℤ
10 zsscn ⊢ ℤ ⊆ ℂ
11 9 10 sstri ⊢ E ⊆ ℂ
12 cnfldbas ⊢ ℂ = Base ℂ fld
13 cnfld0 ⊢ 0 = 0 ℂ fld
14 2 12 13 ress0g ⊢ ℂ fld ∈ Mnd ∧ 0 ∈ E ∧ E ⊆ ℂ → 0 = 0 R
15 6 7 11 14 mp3an ⊢ 0 = 0 R