Metamath Proof Explorer


Theorem 5recm6rec

Description: One fifth minus one sixth. (Contributed by Scott Fenton, 9-Jan-2017)

Ref Expression
Assertion 5recm6rec ⊢ 1 5 − 1 6 = 1 30

Proof

Step Hyp Ref Expression
1 5cn ⊢ 5 ∈ ℂ
2 6cn ⊢ 6 ∈ ℂ
3 5re ⊢ 5 ∈ ℝ
4 5pos ⊢ 0 < 5
5 3 4 gt0ne0ii ⊢ 5 ≠ 0
6 6re ⊢ 6 ∈ ℝ
7 6pos ⊢ 0 < 6
8 6 7 gt0ne0ii ⊢ 6 ≠ 0
9 1 2 5 8 subreci ⊢ 1 5 − 1 6 = 6 − 5 5 ⋅ 6
10 ax-1cn ⊢ 1 ∈ ℂ
11 5p1e6 ⊢ 5 + 1 = 6
12 2 1 10 11 subaddrii ⊢ 6 − 5 = 1
13 6t5e30 ⊢ 6 ⋅ 5 = 30
14 2 1 13 mulcomli ⊢ 5 ⋅ 6 = 30
15 12 14 oveq12i ⊢ 6 − 5 5 ⋅ 6 = 1 30
16 9 15 eqtri ⊢ 1 5 − 1 6 = 1 30