Metamath Proof Explorer


Theorem asclcom

Description: Scalars are commutative after being lifted.

However, the scalars themselves are not necessarily commutative if the algebra is not a faithful module. For example, Let F be the 2 by 2 upper triangular matrix algebra over a commutative ring W . It is provable that F is in general non-commutative. Define scalar multiplication C .x. X as multipying the top-left entry, which is a "vector" element of W , of the "scalar" C , which is now an upper triangular matrix, with the "vector" X e. ( BaseW ) .

Equivalently, the algebra scalars function is not necessarily injective unless the algebra is faithful. Therefore, all "scalar injection" was renamed.

Alternate proof involves assa2ass , assa2ass2 , and asclval , by setting X and Y the multiplicative identity of the algebra.

(Contributed by Zhi Wang, 11-Sep-2025)

Ref Expression
Hypotheses asclelbas.a A = algSc W
asclelbas.f F = Scalar W
asclelbas.b B = Base F
asclelbas.w φ W AssAlg
asclelbas.c φ C B
asclcom.m ˙ = F
asclcom.d φ D B
Assertion asclcom φ A C ˙ D = A D ˙ C

Proof

Step Hyp Ref Expression
1 asclelbas.a A = algSc W
2 asclelbas.f F = Scalar W
3 asclelbas.b B = Base F
4 asclelbas.w φ W AssAlg
5 asclelbas.c φ C B
6 asclcom.m ˙ = F
7 asclcom.d φ D B
8 1 2 3 4 7 asclelbas φ A D Base W
9 eqid Base W = Base W
10 eqid W = W
11 eqid W = W
12 1 2 3 9 10 11 asclmul1 W AssAlg C B A D Base W A C W A D = C W A D
13 1 2 3 9 10 11 asclmul2 W AssAlg C B A D Base W A D W A C = C W A D
14 12 13 eqtr4d W AssAlg C B A D Base W A C W A D = A D W A C
15 4 5 8 14 syl3anc φ A C W A D = A D W A C
16 1 2 3 10 6 ascldimul W AssAlg C B D B A C ˙ D = A C W A D
17 4 5 7 16 syl3anc φ A C ˙ D = A C W A D
18 1 2 3 10 6 ascldimul W AssAlg D B C B A D ˙ C = A D W A C
19 4 7 5 18 syl3anc φ A D ˙ C = A D W A C
20 15 17 19 3eqtr4d φ A C ˙ D = A D ˙ C