Metamath Proof Explorer


Theorem ax6e2ndeq

Description: "At least two sets exist" expressed in the form of dtru is logically equivalent to the same expressed in a form similar to ax6e if dtru is false implies u = v . ax6e2ndeq is derived from ax6e2ndeqVD . (Contributed by Alan Sare, 25-Mar-2014) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion ax6e2ndeq ⊢ ¬ ∀ x x = y ∨ u = v ↔ ∃ x ∃ y x = u ∧ y = v

Proof

Step Hyp Ref Expression
1 ax6e2nd ⊢ ¬ ∀ x x = y → ∃ x ∃ y x = u ∧ y = v
2 ax6e2eq ⊢ ∀ x x = y → u = v → ∃ x ∃ y x = u ∧ y = v
3 1 a1d ⊢ ¬ ∀ x x = y → u = v → ∃ x ∃ y x = u ∧ y = v
4 2 3 pm2.61i ⊢ u = v → ∃ x ∃ y x = u ∧ y = v
5 1 4 jaoi ⊢ ¬ ∀ x x = y ∨ u = v → ∃ x ∃ y x = u ∧ y = v
6 olc ⊢ u = v → ¬ ∀ x x = y ∨ u = v
7 6 a1d ⊢ u = v → ∃ x ∃ y x = u ∧ y = v → ¬ ∀ x x = y ∨ u = v
8 excom ⊢ ∃ x ∃ y x = u ∧ y = v ↔ ∃ y ∃ x x = u ∧ y = v
9 neeq1 ⊢ x = u → x ≠ v ↔ u ≠ v
10 9 biimprcd ⊢ u ≠ v → x = u → x ≠ v
11 10 adantrd ⊢ u ≠ v → x = u ∧ y = v → x ≠ v
12 simpr ⊢ x = u ∧ y = v → y = v
13 12 a1i ⊢ u ≠ v → x = u ∧ y = v → y = v
14 neeq2 ⊢ y = v → x ≠ y ↔ x ≠ v
15 14 biimprcd ⊢ x ≠ v → y = v → x ≠ y
16 11 13 15 syl6c ⊢ u ≠ v → x = u ∧ y = v → x ≠ y
17 sp ⊢ ∀ x x = y → x = y
18 17 necon3ai ⊢ x ≠ y → ¬ ∀ x x = y
19 16 18 syl6 ⊢ u ≠ v → x = u ∧ y = v → ¬ ∀ x x = y
20 19 eximdv ⊢ u ≠ v → ∃ x x = u ∧ y = v → ∃ x ¬ ∀ x x = y
21 nfnae ⊢ Ⅎ x ¬ ∀ x x = y
22 21 19.9 ⊢ ∃ x ¬ ∀ x x = y ↔ ¬ ∀ x x = y
23 20 22 imbitrdi ⊢ u ≠ v → ∃ x x = u ∧ y = v → ¬ ∀ x x = y
24 23 eximdv ⊢ u ≠ v → ∃ y ∃ x x = u ∧ y = v → ∃ y ¬ ∀ x x = y
25 8 24 biimtrid ⊢ u ≠ v → ∃ x ∃ y x = u ∧ y = v → ∃ y ¬ ∀ x x = y
26 nfnae ⊢ Ⅎ y ¬ ∀ x x = y
27 26 19.9 ⊢ ∃ y ¬ ∀ x x = y ↔ ¬ ∀ x x = y
28 25 27 imbitrdi ⊢ u ≠ v → ∃ x ∃ y x = u ∧ y = v → ¬ ∀ x x = y
29 orc ⊢ ¬ ∀ x x = y → ¬ ∀ x x = y ∨ u = v
30 28 29 syl6 ⊢ u ≠ v → ∃ x ∃ y x = u ∧ y = v → ¬ ∀ x x = y ∨ u = v
31 7 30 pm2.61ine ⊢ ∃ x ∃ y x = u ∧ y = v → ¬ ∀ x x = y ∨ u = v
32 5 31 impbii ⊢ ¬ ∀ x x = y ∨ u = v ↔ ∃ x ∃ y x = u ∧ y = v