Metamath Proof Explorer


Theorem axlowdimlem11

Description: Lemma for axlowdim . Calculate the value of Q at its distinguished point. (Contributed by Scott Fenton, 21-Apr-2013)

Ref Expression
Hypothesis axlowdimlem10.1 Q=I+111NI+1×0
Assertion axlowdimlem11 QI+1=1

Proof

Step Hyp Ref Expression
1 axlowdimlem10.1 Q=I+111NI+1×0
2 1 fveq1i QI+1=I+111NI+1×0I+1
3 ovex I+1V
4 1ex 1V
5 3 4 fnsn I+11FnI+1
6 c0ex 0V
7 6 fconst 1NI+1×0:1NI+10
8 ffn 1NI+1×0:1NI+101NI+1×0Fn1NI+1
9 7 8 ax-mp 1NI+1×0Fn1NI+1
10 disjdif I+11NI+1=
11 3 snid I+1I+1
12 10 11 pm3.2i I+11NI+1=I+1I+1
13 fvun1 I+11FnI+11NI+1×0Fn1NI+1I+11NI+1=I+1I+1I+111NI+1×0I+1=I+11I+1
14 5 9 12 13 mp3an I+111NI+1×0I+1=I+11I+1
15 3 4 fvsn I+11I+1=1
16 2 14 15 3eqtri QI+1=1