Metamath Proof Explorer


Theorem axlowdimlem8

Description: Lemma for axlowdim . Calculate the value of P at three. (Contributed by Scott Fenton, 21-Apr-2013)

Ref Expression
Hypothesis axlowdimlem7.1 ⊢ P = 3 − 1 ∪ 1 … N ∖ 3 × 0
Assertion axlowdimlem8 ⊢ P ⁡ 3 = − 1

Proof

Step Hyp Ref Expression
1 axlowdimlem7.1 ⊢ P = 3 − 1 ∪ 1 … N ∖ 3 × 0
2 1 fveq1i ⊢ P ⁡ 3 = 3 − 1 ∪ 1 … N ∖ 3 × 0 ⁡ 3
3 3ex ⊢ 3 ∈ V
4 negex ⊢ − 1 ∈ V
5 3 4 fnsn ⊢ 3 − 1 Fn 3
6 c0ex ⊢ 0 ∈ V
7 6 fconst ⊢ 1 … N ∖ 3 × 0 : 1 … N ∖ 3 ⟶ 0
8 ffn ⊢ 1 … N ∖ 3 × 0 : 1 … N ∖ 3 ⟶ 0 → 1 … N ∖ 3 × 0 Fn 1 … N ∖ 3
9 7 8 ax-mp ⊢ 1 … N ∖ 3 × 0 Fn 1 … N ∖ 3
10 disjdif ⊢ 3 ∩ 1 … N ∖ 3 = ∅
11 3 snid ⊢ 3 ∈ 3
12 10 11 pm3.2i ⊢ 3 ∩ 1 … N ∖ 3 = ∅ ∧ 3 ∈ 3
13 fvun1 ⊢ 3 − 1 Fn 3 ∧ 1 … N ∖ 3 × 0 Fn 1 … N ∖ 3 ∧ 3 ∩ 1 … N ∖ 3 = ∅ ∧ 3 ∈ 3 → 3 − 1 ∪ 1 … N ∖ 3 × 0 ⁡ 3 = 3 − 1 ⁡ 3
14 5 9 12 13 mp3an ⊢ 3 − 1 ∪ 1 … N ∖ 3 × 0 ⁡ 3 = 3 − 1 ⁡ 3
15 3 4 fvsn ⊢ 3 − 1 ⁡ 3 = − 1
16 2 14 15 3eqtri ⊢ P ⁡ 3 = − 1