Metamath Proof Explorer


Theorem bru3val

Description: An alternate way to express the basic 3rd root of unity. (Contributed by AV, 24-Oct-2026)

Ref Expression
Hypothesis bru3eq.w No typesetting found for |- W = ( bRoU ` 3 ) with typecode |-
Assertion bru3val ⊢ W = - 1 + i ⁢ 3 2

Proof

Step Hyp Ref Expression
1 bru3eq.w Could not format W = ( bRoU ` 3 ) : No typesetting found for |- W = ( bRoU ` 3 ) with typecode |-
2 3nn ⊢ 3 ∈ ℕ
3 bruval3 Could not format ( 3 e. NN -> ( bRoU ` 3 ) = ( ( cos ` ( ( 2 x. _pi ) / 3 ) ) + ( _i x. ( sin ` ( ( 2 x. _pi ) / 3 ) ) ) ) ) : No typesetting found for |- ( 3 e. NN -> ( bRoU ` 3 ) = ( ( cos ` ( ( 2 x. _pi ) / 3 ) ) + ( _i x. ( sin ` ( ( 2 x. _pi ) / 3 ) ) ) ) ) with typecode |-
4 2 3 ax-mp Could not format ( bRoU ` 3 ) = ( ( cos ` ( ( 2 x. _pi ) / 3 ) ) + ( _i x. ( sin ` ( ( 2 x. _pi ) / 3 ) ) ) ) : No typesetting found for |- ( bRoU ` 3 ) = ( ( cos ` ( ( 2 x. _pi ) / 3 ) ) + ( _i x. ( sin ` ( ( 2 x. _pi ) / 3 ) ) ) ) with typecode |-
5 ax-icn ⊢ i ∈ ℂ
6 3re ⊢ 3 ∈ ℝ
7 3pos ⊢ 0 < 3
8 6 7 sqrtpclii ⊢ 3 ∈ ℝ
9 8 recni ⊢ 3 ∈ ℂ
10 2cn ⊢ 2 ∈ ℂ
11 2ne0 ⊢ 2 ≠ 0
12 5 9 10 11 divassi ⊢ i ⁢ 3 2 = i ⁢ 3 2
13 12 oveq2i ⊢ − 1 2 + i ⁢ 3 2 = − 1 2 + i ⁢ 3 2
14 neg1cn ⊢ − 1 ∈ ℂ
15 5 9 mulcli ⊢ i ⁢ 3 ∈ ℂ
16 14 15 10 11 divdiri ⊢ - 1 + i ⁢ 3 2 = − 1 2 + i ⁢ 3 2
17 picn ⊢ π ∈ ℂ
18 3cn ⊢ 3 ∈ ℂ
19 3ne0 ⊢ 3 ≠ 0
20 10 17 18 19 divassi ⊢ 2 ⁢ π 3 = 2 ⁢ π 3
21 20 fveq2i ⊢ cos ⁡ 2 ⁢ π 3 = cos ⁡ 2 ⁢ π 3
22 17 18 19 divcli ⊢ π 3 ∈ ℂ
23 cos2t ⊢ π 3 ∈ ℂ → cos ⁡ 2 ⁢ π 3 = 2 ⁢ cos ⁡ π 3 2 − 1
24 22 23 ax-mp ⊢ cos ⁡ 2 ⁢ π 3 = 2 ⁢ cos ⁡ π 3 2 − 1
25 sincos3rdpi ⊢ sin ⁡ π 3 = 3 2 ∧ cos ⁡ π 3 = 1 2
26 25 simpri ⊢ cos ⁡ π 3 = 1 2
27 26 oveq1i ⊢ cos ⁡ π 3 2 = 1 2 2
28 10 11 sqrecii ⊢ 1 2 2 = 1 2 2
29 27 28 eqtri ⊢ cos ⁡ π 3 2 = 1 2 2
30 29 oveq2i ⊢ 2 ⁢ cos ⁡ π 3 2 = 2 ⁢ 1 2 2
31 30 oveq1i ⊢ 2 ⁢ cos ⁡ π 3 2 − 1 = 2 ⁢ 1 2 2 − 1
32 24 31 eqtri ⊢ cos ⁡ 2 ⁢ π 3 = 2 ⁢ 1 2 2 − 1
33 10 sqvali ⊢ 2 2 = 2 ⋅ 2
34 33 oveq2i ⊢ 1 2 2 = 1 2 ⋅ 2
35 34 oveq2i ⊢ 2 ⁢ 1 2 2 = 2 ⁢ 1 2 ⋅ 2
36 ax-1cn ⊢ 1 ∈ ℂ
37 10 10 mulcli ⊢ 2 ⋅ 2 ∈ ℂ
38 2t2e4 ⊢ 2 ⋅ 2 = 4
39 4ne0 ⊢ 4 ≠ 0
40 38 39 eqnetri ⊢ 2 ⋅ 2 ≠ 0
41 10 36 37 40 divassi ⊢ 2 ⋅ 1 2 ⋅ 2 = 2 ⁢ 1 2 ⋅ 2
42 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
43 divcan5 ⊢ 1 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⋅ 1 2 ⋅ 2 = 1 2
44 36 42 42 43 mp3an ⊢ 2 ⋅ 1 2 ⋅ 2 = 1 2
45 41 44 eqtr3i ⊢ 2 ⁢ 1 2 ⋅ 2 = 1 2
46 35 45 eqtri ⊢ 2 ⁢ 1 2 2 = 1 2
47 46 oveq1i ⊢ 2 ⁢ 1 2 2 − 1 = 1 2 − 1
48 2div2e1 ⊢ 2 2 = 1
49 48 eqcomi ⊢ 1 = 2 2
50 49 oveq2i ⊢ 1 2 − 1 = 1 2 − 2 2
51 divsubdir ⊢ 1 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 1 − 2 2 = 1 2 − 2 2
52 36 10 42 51 mp3an ⊢ 1 − 2 2 = 1 2 − 2 2
53 50 52 eqtr4i ⊢ 1 2 − 1 = 1 − 2 2
54 10 36 negsubdi2i ⊢ − 2 − 1 = 1 − 2
55 2m1e1 ⊢ 2 − 1 = 1
56 55 negeqi ⊢ − 2 − 1 = − 1
57 54 56 eqtr3i ⊢ 1 − 2 = − 1
58 57 oveq1i ⊢ 1 − 2 2 = − 1 2
59 47 53 58 3eqtri ⊢ 2 ⁢ 1 2 2 − 1 = − 1 2
60 21 32 59 3eqtri ⊢ cos ⁡ 2 ⁢ π 3 = − 1 2
61 20 fveq2i ⊢ sin ⁡ 2 ⁢ π 3 = sin ⁡ 2 ⁢ π 3
62 sin2t ⊢ π 3 ∈ ℂ → sin ⁡ 2 ⁢ π 3 = 2 ⁢ sin ⁡ π 3 ⁢ cos ⁡ π 3
63 22 62 ax-mp ⊢ sin ⁡ 2 ⁢ π 3 = 2 ⁢ sin ⁡ π 3 ⁢ cos ⁡ π 3
64 oveq12 ⊢ sin ⁡ π 3 = 3 2 ∧ cos ⁡ π 3 = 1 2 → sin ⁡ π 3 ⁢ cos ⁡ π 3 = 3 2 ⁢ 1 2
65 25 64 ax-mp ⊢ sin ⁡ π 3 ⁢ cos ⁡ π 3 = 3 2 ⁢ 1 2
66 65 oveq2i ⊢ 2 ⁢ sin ⁡ π 3 ⁢ cos ⁡ π 3 = 2 ⁢ 3 2 ⁢ 1 2
67 9 10 11 divcli ⊢ 3 2 ∈ ℂ
68 67 10 11 divreci ⊢ 3 2 2 = 3 2 ⁢ 1 2
69 68 eqcomi ⊢ 3 2 ⁢ 1 2 = 3 2 2
70 69 oveq2i ⊢ 2 ⁢ 3 2 ⁢ 1 2 = 2 ⁢ 3 2 2
71 67 10 11 divcan2i ⊢ 2 ⁢ 3 2 2 = 3 2
72 66 70 71 3eqtri ⊢ 2 ⁢ sin ⁡ π 3 ⁢ cos ⁡ π 3 = 3 2
73 61 63 72 3eqtri ⊢ sin ⁡ 2 ⁢ π 3 = 3 2
74 73 oveq2i ⊢ i ⁢ sin ⁡ 2 ⁢ π 3 = i ⁢ 3 2
75 60 74 oveq12i ⊢ cos ⁡ 2 ⁢ π 3 + i ⁢ sin ⁡ 2 ⁢ π 3 = − 1 2 + i ⁢ 3 2
76 13 16 75 3eqtr4ri ⊢ cos ⁡ 2 ⁢ π 3 + i ⁢ sin ⁡ 2 ⁢ π 3 = - 1 + i ⁢ 3 2
77 1 4 76 3eqtri ⊢ W = - 1 + i ⁢ 3 2