Metamath Proof Explorer


Theorem btwncomand

Description: Deduction form of btwncom . (Contributed by Scott Fenton, 14-Oct-2013)

Ref Expression
Hypotheses btwncomand.1 ⊢ φ → N ∈ ℕ
btwncomand.2 ⊢ φ → A ∈ 𝔼 ⁡ N
btwncomand.3 ⊢ φ → B ∈ 𝔼 ⁡ N
btwncomand.4 ⊢ φ → C ∈ 𝔼 ⁡ N
btwncomand.5 ⊢ φ ∧ ψ → A Btwn B C
Assertion btwncomand ⊢ φ ∧ ψ → A Btwn C B

Proof

Step Hyp Ref Expression
1 btwncomand.1 ⊢ φ → N ∈ ℕ
2 btwncomand.2 ⊢ φ → A ∈ 𝔼 ⁡ N
3 btwncomand.3 ⊢ φ → B ∈ 𝔼 ⁡ N
4 btwncomand.4 ⊢ φ → C ∈ 𝔼 ⁡ N
5 btwncomand.5 ⊢ φ ∧ ψ → A Btwn B C
6 btwncom ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N → A Btwn B C ↔ A Btwn C B
7 1 2 3 4 6 syl13anc ⊢ φ → A Btwn B C ↔ A Btwn C B
8 7 adantr ⊢ φ ∧ ψ → A Btwn B C ↔ A Btwn C B
9 5 8 mpbid ⊢ φ ∧ ψ → A Btwn C B