Metamath Proof Explorer


Theorem cdivcncf

Description: Division with a constant numerator is continuous. (Contributed by Mario Carneiro, 28-Dec-2016)

Ref Expression
Hypothesis cdivcncf.1 ⊢ F = x ∈ ℂ ∖ 0 ⟼ A x
Assertion cdivcncf ⊢ A ∈ ℂ → F : ℂ ∖ 0 ⟶cn ℂ

Proof

Step Hyp Ref Expression
1 cdivcncf.1 ⊢ F = x ∈ ℂ ∖ 0 ⟼ A x
2 eqid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld
3 2 cnfldtopon ⊢ TopOpen ⁡ ℂ fld ∈ TopOn ⁡ ℂ
4 3 a1i ⊢ A ∈ ℂ → TopOpen ⁡ ℂ fld ∈ TopOn ⁡ ℂ
5 difss ⊢ ℂ ∖ 0 ⊆ ℂ
6 resttopon ⊢ TopOpen ⁡ ℂ fld ∈ TopOn ⁡ ℂ ∧ ℂ ∖ 0 ⊆ ℂ → TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 ∈ TopOn ⁡ ℂ ∖ 0
7 4 5 6 sylancl ⊢ A ∈ ℂ → TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 ∈ TopOn ⁡ ℂ ∖ 0
8 id ⊢ A ∈ ℂ → A ∈ ℂ
9 7 4 8 cnmptc ⊢ A ∈ ℂ → x ∈ ℂ ∖ 0 ⟼ A ∈ TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 Cn TopOpen ⁡ ℂ fld
10 7 cnmptid ⊢ A ∈ ℂ → x ∈ ℂ ∖ 0 ⟼ x ∈ TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 Cn TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0
11 eqid ⊢ TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 = TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0
12 2 11 divcn ⊢ ÷ ∈ TopOpen ⁡ ℂ fld × t TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 Cn TopOpen ⁡ ℂ fld
13 12 a1i ⊢ A ∈ ℂ → ÷ ∈ TopOpen ⁡ ℂ fld × t TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 Cn TopOpen ⁡ ℂ fld
14 7 9 10 13 cnmpt12f ⊢ A ∈ ℂ → x ∈ ℂ ∖ 0 ⟼ A x ∈ TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 Cn TopOpen ⁡ ℂ fld
15 ssid ⊢ ℂ ⊆ ℂ
16 3 toponrestid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ
17 2 11 16 cncfcn ⊢ ℂ ∖ 0 ⊆ ℂ ∧ ℂ ⊆ ℂ → ℂ ∖ 0 ⟶cn ℂ = TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 Cn TopOpen ⁡ ℂ fld
18 5 15 17 mp2an ⊢ ℂ ∖ 0 ⟶cn ℂ = TopOpen ⁡ ℂ fld ↾ 𝑡 ℂ ∖ 0 Cn TopOpen ⁡ ℂ fld
19 14 1 18 3eltr4g ⊢ A ∈ ℂ → F : ℂ ∖ 0 ⟶cn ℂ