Metamath Proof Explorer


Theorem cdlemb2

Description: Given two atoms not under the fiducial (reference) co-atom W , there is a third. Lemma B in Crawley p. 112. (Contributed by NM, 30-May-2012)

Ref Expression
Hypotheses cdlemb2.l ⊢ ≤ ˙ = ≤ K
cdlemb2.j ⊢ ∨ ˙ = join ⁡ K
cdlemb2.a ⊢ A = Atoms ⁡ K
cdlemb2.h ⊢ H = LHyp ⁡ K
Assertion cdlemb2 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ∃ r ∈ A ¬ r ≤ ˙ W ∧ ¬ r ≤ ˙ P ∨ ˙ Q

Proof

Step Hyp Ref Expression
1 cdlemb2.l ⊢ ≤ ˙ = ≤ K
2 cdlemb2.j ⊢ ∨ ˙ = join ⁡ K
3 cdlemb2.a ⊢ A = Atoms ⁡ K
4 cdlemb2.h ⊢ H = LHyp ⁡ K
5 simp1l ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → K ∈ HL
6 simp2ll ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → P ∈ A
7 simp2rl ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → Q ∈ A
8 simp1r ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → W ∈ H
9 eqid ⊢ Base K = Base K
10 9 4 lhpbase ⊢ W ∈ H → W ∈ Base K
11 8 10 syl ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → W ∈ Base K
12 simp3 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → P ≠ Q
13 eqid ⊢ 1. ⁡ K = 1. ⁡ K
14 eqid ⊢ ⋖ K = ⋖ K
15 13 14 4 lhp1cvr ⊢ K ∈ HL ∧ W ∈ H → W ⋖ K 1. ⁡ K
16 15 3ad2ant1 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → W ⋖ K 1. ⁡ K
17 simp2lr ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ¬ P ≤ ˙ W
18 simp2rr ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ¬ Q ≤ ˙ W
19 9 1 2 13 14 3 cdlemb ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ W ∈ Base K ∧ P ≠ Q ∧ W ⋖ K 1. ⁡ K ∧ ¬ P ≤ ˙ W ∧ ¬ Q ≤ ˙ W → ∃ r ∈ A ¬ r ≤ ˙ W ∧ ¬ r ≤ ˙ P ∨ ˙ Q
20 5 6 7 11 12 16 17 18 19 syl323anc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ P ≠ Q → ∃ r ∈ A ¬ r ≤ ˙ W ∧ ¬ r ≤ ˙ P ∨ ˙ Q