Metamath Proof Explorer


Theorem cdlemd9

Description: Part of proof of Lemma D in Crawley p. 113. (Contributed by NM, 2-Jun-2012)

Ref Expression
Hypotheses cdlemd4.l ⊢ ≤ ˙ = ≤ K
cdlemd4.j ⊢ ∨ ˙ = join ⁡ K
cdlemd4.a ⊢ A = Atoms ⁡ K
cdlemd4.h ⊢ H = LHyp ⁡ K
cdlemd4.t ⊢ T = LTrn ⁡ K ⁡ W
Assertion cdlemd9 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P → F ⁡ R = G ⁡ R

Proof

Step Hyp Ref Expression
1 cdlemd4.l ⊢ ≤ ˙ = ≤ K
2 cdlemd4.j ⊢ ∨ ˙ = join ⁡ K
3 cdlemd4.a ⊢ A = Atoms ⁡ K
4 cdlemd4.h ⊢ H = LHyp ⁡ K
5 cdlemd4.t ⊢ T = LTrn ⁡ K ⁡ W
6 simpl1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P = P → K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A
7 simpl2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P = P → P ∈ A ∧ ¬ P ≤ ˙ W
8 simpl3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P = P → F ⁡ P = G ⁡ P
9 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P = P → F ⁡ P = P
10 1 2 3 4 5 cdlemd8 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P = P → F ⁡ R = G ⁡ R
11 6 7 8 9 10 syl112anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P = P → F ⁡ R = G ⁡ R
12 simpl11 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → K ∈ HL ∧ W ∈ H
13 simpl2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → P ∈ A ∧ ¬ P ≤ ˙ W
14 simp12l ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P → F ∈ T
15 14 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → F ∈ T
16 1 3 4 5 ltrnel ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W → F ⁡ P ∈ A ∧ ¬ F ⁡ P ≤ ˙ W
17 12 15 13 16 syl3anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → F ⁡ P ∈ A ∧ ¬ F ⁡ P ≤ ˙ W
18 simpr ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → F ⁡ P ≠ P
19 18 necomd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → P ≠ F ⁡ P
20 1 2 3 4 cdlemb2 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P ∈ A ∧ ¬ F ⁡ P ≤ ˙ W ∧ P ≠ F ⁡ P → ∃ s ∈ A ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P
21 12 13 17 19 20 syl121anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → ∃ s ∈ A ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P
22 simp1l1 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A
23 simp1l2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → P ∈ A ∧ ¬ P ≤ ˙ W
24 simp2 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → s ∈ A
25 simp3l ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → ¬ s ≤ ˙ W
26 24 25 jca ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → s ∈ A ∧ ¬ s ≤ ˙ W
27 simp1l3 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → F ⁡ P = G ⁡ P
28 simp3r ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → ¬ s ≤ ˙ P ∨ ˙ F ⁡ P
29 1 2 3 4 5 cdlemd7 ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → F ⁡ R = G ⁡ R
30 22 23 26 27 28 29 syl122anc ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P ∧ s ∈ A ∧ ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → F ⁡ R = G ⁡ R
31 30 rexlimdv3a ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → ∃ s ∈ A ¬ s ≤ ˙ W ∧ ¬ s ≤ ˙ P ∨ ˙ F ⁡ P → F ⁡ R = G ⁡ R
32 21 31 mpd ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P ∧ F ⁡ P ≠ P → F ⁡ R = G ⁡ R
33 11 32 pm2.61dane ⊢ K ∈ HL ∧ W ∈ H ∧ F ∈ T ∧ G ∈ T ∧ R ∈ A ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ F ⁡ P = G ⁡ P → F ⁡ R = G ⁡ R