Metamath Proof Explorer


Theorem clmvs2

Description: A vector plus itself is two times the vector. (Contributed by NM, 1-Feb-2007) (Revised by AV, 21-Sep-2021)

Ref Expression
Hypotheses clmvs1.v ⊢ V = Base W
clmvs1.s ⊢ · ˙ = ⋅ W
clmvs2.a ⊢ + ˙ = + W
Assertion clmvs2 ⊢ W ∈ CMod ∧ A ∈ V → A + ˙ A = 2 · ˙ A

Proof

Step Hyp Ref Expression
1 clmvs1.v ⊢ V = Base W
2 clmvs1.s ⊢ · ˙ = ⋅ W
3 clmvs2.a ⊢ + ˙ = + W
4 df-2 ⊢ 2 = 1 + 1
5 4 oveq1i ⊢ 2 · ˙ A = 1 + 1 · ˙ A
6 5 a1i ⊢ W ∈ CMod ∧ A ∈ V → 2 · ˙ A = 1 + 1 · ˙ A
7 simpl ⊢ W ∈ CMod ∧ A ∈ V → W ∈ CMod
8 eqid ⊢ Scalar ⁡ W = Scalar ⁡ W
9 8 clm1 ⊢ W ∈ CMod → 1 = 1 Scalar ⁡ W
10 clmlmod ⊢ W ∈ CMod → W ∈ LMod
11 eqid ⊢ Base Scalar ⁡ W = Base Scalar ⁡ W
12 eqid ⊢ 1 Scalar ⁡ W = 1 Scalar ⁡ W
13 8 11 12 lmod1cl ⊢ W ∈ LMod → 1 Scalar ⁡ W ∈ Base Scalar ⁡ W
14 10 13 syl ⊢ W ∈ CMod → 1 Scalar ⁡ W ∈ Base Scalar ⁡ W
15 9 14 eqeltrd ⊢ W ∈ CMod → 1 ∈ Base Scalar ⁡ W
16 15 adantr ⊢ W ∈ CMod ∧ A ∈ V → 1 ∈ Base Scalar ⁡ W
17 simpr ⊢ W ∈ CMod ∧ A ∈ V → A ∈ V
18 1 8 2 11 3 clmvsdir ⊢ W ∈ CMod ∧ 1 ∈ Base Scalar ⁡ W ∧ 1 ∈ Base Scalar ⁡ W ∧ A ∈ V → 1 + 1 · ˙ A = 1 · ˙ A + ˙ 1 · ˙ A
19 7 16 16 17 18 syl13anc ⊢ W ∈ CMod ∧ A ∈ V → 1 + 1 · ˙ A = 1 · ˙ A + ˙ 1 · ˙ A
20 1 2 clmvs1 ⊢ W ∈ CMod ∧ A ∈ V → 1 · ˙ A = A
21 20 20 oveq12d ⊢ W ∈ CMod ∧ A ∈ V → 1 · ˙ A + ˙ 1 · ˙ A = A + ˙ A
22 6 19 21 3eqtrrd ⊢ W ∈ CMod ∧ A ∈ V → A + ˙ A = 2 · ˙ A