Metamath Proof Explorer


Theorem coskpi

Description: The absolute value of the cosine of an integer multiple of _pi is 1. (Contributed by NM, 19-Aug-2008)

Ref Expression
Assertion coskpi ⊢ K ∈ ℤ → cos ⁡ K ⁢ π = 1

Proof

Step Hyp Ref Expression
1 zcn ⊢ K ∈ ℤ → K ∈ ℂ
2 2cn ⊢ 2 ∈ ℂ
3 picn ⊢ π ∈ ℂ
4 mul12 ⊢ K ∈ ℂ ∧ 2 ∈ ℂ ∧ π ∈ ℂ → K ⁢ 2 ⁢ π = 2 ⁢ K ⁢ π
5 2 3 4 mp3an23 ⊢ K ∈ ℂ → K ⁢ 2 ⁢ π = 2 ⁢ K ⁢ π
6 1 5 syl ⊢ K ∈ ℤ → K ⁢ 2 ⁢ π = 2 ⁢ K ⁢ π
7 6 fveq2d ⊢ K ∈ ℤ → cos ⁡ K ⁢ 2 ⁢ π = cos ⁡ 2 ⁢ K ⁢ π
8 cos2kpi ⊢ K ∈ ℤ → cos ⁡ K ⁢ 2 ⁢ π = 1
9 zre ⊢ K ∈ ℤ → K ∈ ℝ
10 pire ⊢ π ∈ ℝ
11 remulcl ⊢ K ∈ ℝ ∧ π ∈ ℝ → K ⁢ π ∈ ℝ
12 9 10 11 sylancl ⊢ K ∈ ℤ → K ⁢ π ∈ ℝ
13 12 recnd ⊢ K ∈ ℤ → K ⁢ π ∈ ℂ
14 cos2t ⊢ K ⁢ π ∈ ℂ → cos ⁡ 2 ⁢ K ⁢ π = 2 ⁢ cos ⁡ K ⁢ π 2 − 1
15 13 14 syl ⊢ K ∈ ℤ → cos ⁡ 2 ⁢ K ⁢ π = 2 ⁢ cos ⁡ K ⁢ π 2 − 1
16 7 8 15 3eqtr3rd ⊢ K ∈ ℤ → 2 ⁢ cos ⁡ K ⁢ π 2 − 1 = 1
17 12 recoscld ⊢ K ∈ ℤ → cos ⁡ K ⁢ π ∈ ℝ
18 17 recnd ⊢ K ∈ ℤ → cos ⁡ K ⁢ π ∈ ℂ
19 18 sqcld ⊢ K ∈ ℤ → cos ⁡ K ⁢ π 2 ∈ ℂ
20 mulcl ⊢ 2 ∈ ℂ ∧ cos ⁡ K ⁢ π 2 ∈ ℂ → 2 ⁢ cos ⁡ K ⁢ π 2 ∈ ℂ
21 2 19 20 sylancr ⊢ K ∈ ℤ → 2 ⁢ cos ⁡ K ⁢ π 2 ∈ ℂ
22 ax-1cn ⊢ 1 ∈ ℂ
23 subadd ⊢ 2 ⁢ cos ⁡ K ⁢ π 2 ∈ ℂ ∧ 1 ∈ ℂ ∧ 1 ∈ ℂ → 2 ⁢ cos ⁡ K ⁢ π 2 − 1 = 1 ↔ 1 + 1 = 2 ⁢ cos ⁡ K ⁢ π 2
24 22 22 23 mp3an23 ⊢ 2 ⁢ cos ⁡ K ⁢ π 2 ∈ ℂ → 2 ⁢ cos ⁡ K ⁢ π 2 − 1 = 1 ↔ 1 + 1 = 2 ⁢ cos ⁡ K ⁢ π 2
25 21 24 syl ⊢ K ∈ ℤ → 2 ⁢ cos ⁡ K ⁢ π 2 − 1 = 1 ↔ 1 + 1 = 2 ⁢ cos ⁡ K ⁢ π 2
26 16 25 mpbid ⊢ K ∈ ℤ → 1 + 1 = 2 ⁢ cos ⁡ K ⁢ π 2
27 2t1e2 ⊢ 2 ⋅ 1 = 2
28 df-2 ⊢ 2 = 1 + 1
29 27 28 eqtr2i ⊢ 1 + 1 = 2 ⋅ 1
30 26 29 eqtr3di ⊢ K ∈ ℤ → 2 ⁢ cos ⁡ K ⁢ π 2 = 2 ⋅ 1
31 2cnne0 ⊢ 2 ∈ ℂ ∧ 2 ≠ 0
32 mulcan ⊢ cos ⁡ K ⁢ π 2 ∈ ℂ ∧ 1 ∈ ℂ ∧ 2 ∈ ℂ ∧ 2 ≠ 0 → 2 ⁢ cos ⁡ K ⁢ π 2 = 2 ⋅ 1 ↔ cos ⁡ K ⁢ π 2 = 1
33 22 31 32 mp3an23 ⊢ cos ⁡ K ⁢ π 2 ∈ ℂ → 2 ⁢ cos ⁡ K ⁢ π 2 = 2 ⋅ 1 ↔ cos ⁡ K ⁢ π 2 = 1
34 19 33 syl ⊢ K ∈ ℤ → 2 ⁢ cos ⁡ K ⁢ π 2 = 2 ⋅ 1 ↔ cos ⁡ K ⁢ π 2 = 1
35 30 34 mpbid ⊢ K ∈ ℤ → cos ⁡ K ⁢ π 2 = 1
36 sq1 ⊢ 1 2 = 1
37 35 36 eqtr4di ⊢ K ∈ ℤ → cos ⁡ K ⁢ π 2 = 1 2
38 1re ⊢ 1 ∈ ℝ
39 sqabs ⊢ cos ⁡ K ⁢ π ∈ ℝ ∧ 1 ∈ ℝ → cos ⁡ K ⁢ π 2 = 1 2 ↔ cos ⁡ K ⁢ π = 1
40 17 38 39 sylancl ⊢ K ∈ ℤ → cos ⁡ K ⁢ π 2 = 1 2 ↔ cos ⁡ K ⁢ π = 1
41 37 40 mpbid ⊢ K ∈ ℤ → cos ⁡ K ⁢ π = 1
42 abs1 ⊢ 1 = 1
43 41 42 eqtrdi ⊢ K ∈ ℤ → cos ⁡ K ⁢ π = 1