Metamath Proof Explorer


Theorem djudisj

Description: Disjoint unions with disjoint index sets are disjoint. (Contributed by Stefan O'Rear, 21-Nov-2014)

Ref Expression
Assertion djudisj ⊢ A ∩ B = ∅ → ⋃ x ∈ A x × C ∩ ⋃ y ∈ B y × D = ∅

Proof

Step Hyp Ref Expression
1 djussxp ⊢ ⋃ x ∈ A x × C ⊆ A × V
2 incom ⊢ A × V ∩ ⋃ y ∈ B y × D = ⋃ y ∈ B y × D ∩ A × V
3 djussxp ⊢ ⋃ y ∈ B y × D ⊆ B × V
4 incom ⊢ B × V ∩ A × V = A × V ∩ B × V
5 xpdisj1 ⊢ A ∩ B = ∅ → A × V ∩ B × V = ∅
6 4 5 eqtrid ⊢ A ∩ B = ∅ → B × V ∩ A × V = ∅
7 ssdisj ⊢ ⋃ y ∈ B y × D ⊆ B × V ∧ B × V ∩ A × V = ∅ → ⋃ y ∈ B y × D ∩ A × V = ∅
8 3 6 7 sylancr ⊢ A ∩ B = ∅ → ⋃ y ∈ B y × D ∩ A × V = ∅
9 2 8 eqtrid ⊢ A ∩ B = ∅ → A × V ∩ ⋃ y ∈ B y × D = ∅
10 ssdisj ⊢ ⋃ x ∈ A x × C ⊆ A × V ∧ A × V ∩ ⋃ y ∈ B y × D = ∅ → ⋃ x ∈ A x × C ∩ ⋃ y ∈ B y × D = ∅
11 1 9 10 sylancr ⊢ A ∩ B = ∅ → ⋃ x ∈ A x × C ∩ ⋃ y ∈ B y × D = ∅