Metamath Proof Explorer


Theorem expcomd

Description: Deduction form of expcom . (Contributed by Alan Sare, 22-Jul-2012)

Ref Expression
Hypothesis expcomd.1 ⊢ φ → ψ ∧ χ → θ
Assertion expcomd ⊢ φ → χ → ψ → θ

Proof

Step Hyp Ref Expression
1 expcomd.1 ⊢ φ → ψ ∧ χ → θ
2 1 expd ⊢ φ → ψ → χ → θ
3 2 com23 ⊢ φ → χ → ψ → θ