Metamath Proof Explorer


Theorem filtop

Description: The underlying set belongs to the filter. (Contributed by FL, 20-Jul-2007) (Revised by Stefan O'Rear, 28-Jul-2015)

Ref Expression
Assertion filtop ⊢ F ∈ Fil ⁡ X → X ∈ F

Proof

Step Hyp Ref Expression
1 filfbas ⊢ F ∈ Fil ⁡ X → F ∈ fBas ⁡ X
2 fbasne0 ⊢ F ∈ fBas ⁡ X → F ≠ ∅
3 1 2 syl ⊢ F ∈ Fil ⁡ X → F ≠ ∅
4 n0 ⊢ F ≠ ∅ ↔ ∃ x x ∈ F
5 filelss ⊢ F ∈ Fil ⁡ X ∧ x ∈ F → x ⊆ X
6 ssid ⊢ X ⊆ X
7 filss ⊢ F ∈ Fil ⁡ X ∧ x ∈ F ∧ X ⊆ X ∧ x ⊆ X → X ∈ F
8 7 3exp2 ⊢ F ∈ Fil ⁡ X → x ∈ F → X ⊆ X → x ⊆ X → X ∈ F
9 8 imp ⊢ F ∈ Fil ⁡ X ∧ x ∈ F → X ⊆ X → x ⊆ X → X ∈ F
10 6 9 mpi ⊢ F ∈ Fil ⁡ X ∧ x ∈ F → x ⊆ X → X ∈ F
11 5 10 mpd ⊢ F ∈ Fil ⁡ X ∧ x ∈ F → X ∈ F
12 11 ex ⊢ F ∈ Fil ⁡ X → x ∈ F → X ∈ F
13 12 exlimdv ⊢ F ∈ Fil ⁡ X → ∃ x x ∈ F → X ∈ F
14 4 13 biimtrid ⊢ F ∈ Fil ⁡ X → F ≠ ∅ → X ∈ F
15 3 14 mpd ⊢ F ∈ Fil ⁡ X → X ∈ F