Metamath Proof Explorer


Theorem flt4ALT

Description: Fermat's last theorem for the exponent four, derived from Fermat's right triangle theorem (which is not proved yet, see fermrtt: after a proof is available, the hypothesis flt4ALT.r can be removed - TODO-AV). (Contributed by AV, 15-Sep-2026) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses flt4.a ⊢ φ → A ∈ ℕ
flt4.b ⊢ φ → B ∈ ℕ
flt4.c ⊢ φ → C ∈ ℕ
flt4ALT.r ⊢ φ → ∀ a ∈ ℕ ∀ b ∈ ℕ ∀ c ∈ ℕ a 4 − b 4 ≠ c 2
Assertion flt4ALT ⊢ φ → A 4 + B 4 ≠ C 4

Proof

Step Hyp Ref Expression
1 flt4.a ⊢ φ → A ∈ ℕ
2 flt4.b ⊢ φ → B ∈ ℕ
3 flt4.c ⊢ φ → C ∈ ℕ
4 flt4ALT.r ⊢ φ → ∀ a ∈ ℕ ∀ b ∈ ℕ ∀ c ∈ ℕ a 4 − b 4 ≠ c 2
5 1 nnsqcld ⊢ φ → A 2 ∈ ℕ
6 3 2 5 3jca ⊢ φ → C ∈ ℕ ∧ B ∈ ℕ ∧ A 2 ∈ ℕ
7 oveq1 ⊢ a = C → a 4 = C 4
8 7 oveq1d ⊢ a = C → a 4 − b 4 = C 4 − b 4
9 8 neeq1d ⊢ a = C → a 4 − b 4 ≠ c 2 ↔ C 4 − b 4 ≠ c 2
10 oveq1 ⊢ b = B → b 4 = B 4
11 10 oveq2d ⊢ b = B → C 4 − b 4 = C 4 − B 4
12 11 neeq1d ⊢ b = B → C 4 − b 4 ≠ c 2 ↔ C 4 − B 4 ≠ c 2
13 oveq1 ⊢ c = A 2 → c 2 = A 2 2
14 13 neeq2d ⊢ c = A 2 → C 4 − B 4 ≠ c 2 ↔ C 4 − B 4 ≠ A 2 2
15 9 12 14 rspc3v ⊢ C ∈ ℕ ∧ B ∈ ℕ ∧ A 2 ∈ ℕ → ∀ a ∈ ℕ ∀ b ∈ ℕ ∀ c ∈ ℕ a 4 − b 4 ≠ c 2 → C 4 − B 4 ≠ A 2 2
16 6 4 15 sylc ⊢ φ → C 4 − B 4 ≠ A 2 2
17 16 neneqd ⊢ φ → ¬ C 4 − B 4 = A 2 2
18 4nn0 ⊢ 4 ∈ ℕ 0
19 18 a1i ⊢ φ → 4 ∈ ℕ 0
20 3 19 nnexpcld ⊢ φ → C 4 ∈ ℕ
21 20 nncnd ⊢ φ → C 4 ∈ ℂ
22 2 19 nnexpcld ⊢ φ → B 4 ∈ ℕ
23 22 nncnd ⊢ φ → B 4 ∈ ℂ
24 1 19 nnexpcld ⊢ φ → A 4 ∈ ℕ
25 24 nncnd ⊢ φ → A 4 ∈ ℂ
26 21 23 25 subadd2d ⊢ φ → C 4 − B 4 = A 4 ↔ A 4 + B 4 = C 4
27 1 nncnd ⊢ φ → A ∈ ℂ
28 27 exp4sqsq ⊢ φ → A 4 = A 2 2
29 28 eqeq2d ⊢ φ → C 4 − B 4 = A 4 ↔ C 4 − B 4 = A 2 2
30 26 29 bitr3d ⊢ φ → A 4 + B 4 = C 4 ↔ C 4 − B 4 = A 2 2
31 17 30 mtbird ⊢ φ → ¬ A 4 + B 4 = C 4
32 31 neqned ⊢ φ → A 4 + B 4 ≠ C 4