Metamath Proof Explorer


Theorem funpsstri

Description: A condition for subset trichotomy for functions. (Contributed by Scott Fenton, 19-Apr-2011)

Ref Expression
Assertion funpsstri ⊢ Fun ⁡ H ∧ F ⊆ H ∧ G ⊆ H ∧ dom ⁡ F ⊆ dom ⁡ G ∨ dom ⁡ G ⊆ dom ⁡ F → F ⊂ G ∨ F = G ∨ G ⊂ F

Proof

Step Hyp Ref Expression
1 funssres ⊢ Fun ⁡ H ∧ F ⊆ H → H ↾ dom ⁡ F = F
2 1 ex ⊢ Fun ⁡ H → F ⊆ H → H ↾ dom ⁡ F = F
3 funssres ⊢ Fun ⁡ H ∧ G ⊆ H → H ↾ dom ⁡ G = G
4 3 ex ⊢ Fun ⁡ H → G ⊆ H → H ↾ dom ⁡ G = G
5 2 4 anim12d ⊢ Fun ⁡ H → F ⊆ H ∧ G ⊆ H → H ↾ dom ⁡ F = F ∧ H ↾ dom ⁡ G = G
6 ssres2 ⊢ dom ⁡ F ⊆ dom ⁡ G → H ↾ dom ⁡ F ⊆ H ↾ dom ⁡ G
7 ssres2 ⊢ dom ⁡ G ⊆ dom ⁡ F → H ↾ dom ⁡ G ⊆ H ↾ dom ⁡ F
8 6 7 orim12i ⊢ dom ⁡ F ⊆ dom ⁡ G ∨ dom ⁡ G ⊆ dom ⁡ F → H ↾ dom ⁡ F ⊆ H ↾ dom ⁡ G ∨ H ↾ dom ⁡ G ⊆ H ↾ dom ⁡ F
9 sseq12 ⊢ H ↾ dom ⁡ F = F ∧ H ↾ dom ⁡ G = G → H ↾ dom ⁡ F ⊆ H ↾ dom ⁡ G ↔ F ⊆ G
10 sseq12 ⊢ H ↾ dom ⁡ G = G ∧ H ↾ dom ⁡ F = F → H ↾ dom ⁡ G ⊆ H ↾ dom ⁡ F ↔ G ⊆ F
11 10 ancoms ⊢ H ↾ dom ⁡ F = F ∧ H ↾ dom ⁡ G = G → H ↾ dom ⁡ G ⊆ H ↾ dom ⁡ F ↔ G ⊆ F
12 9 11 orbi12d ⊢ H ↾ dom ⁡ F = F ∧ H ↾ dom ⁡ G = G → H ↾ dom ⁡ F ⊆ H ↾ dom ⁡ G ∨ H ↾ dom ⁡ G ⊆ H ↾ dom ⁡ F ↔ F ⊆ G ∨ G ⊆ F
13 8 12 imbitrid ⊢ H ↾ dom ⁡ F = F ∧ H ↾ dom ⁡ G = G → dom ⁡ F ⊆ dom ⁡ G ∨ dom ⁡ G ⊆ dom ⁡ F → F ⊆ G ∨ G ⊆ F
14 5 13 syl6 ⊢ Fun ⁡ H → F ⊆ H ∧ G ⊆ H → dom ⁡ F ⊆ dom ⁡ G ∨ dom ⁡ G ⊆ dom ⁡ F → F ⊆ G ∨ G ⊆ F
15 14 3imp ⊢ Fun ⁡ H ∧ F ⊆ H ∧ G ⊆ H ∧ dom ⁡ F ⊆ dom ⁡ G ∨ dom ⁡ G ⊆ dom ⁡ F → F ⊆ G ∨ G ⊆ F
16 sspsstri ⊢ F ⊆ G ∨ G ⊆ F ↔ F ⊂ G ∨ F = G ∨ G ⊂ F
17 15 16 sylib ⊢ Fun ⁡ H ∧ F ⊆ H ∧ G ⊆ H ∧ dom ⁡ F ⊆ dom ⁡ G ∨ dom ⁡ G ⊆ dom ⁡ F → F ⊂ G ∨ F = G ∨ G ⊂ F