Metamath Proof Explorer


Theorem hashf1dmrn

Description: The size of the domain of a one-to-one set function is equal to the size of its range. (Contributed by BTernaryTau, 1-Oct-2023)

Ref Expression
Assertion hashf1dmrn ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → A = ran ⁡ F

Proof

Step Hyp Ref Expression
1 f1fun ⊢ F : A ⟶ 1-1 B → Fun ⁡ F
2 hashfundm ⊢ F ∈ V ∧ Fun ⁡ F → F = dom ⁡ F
3 1 2 sylan2 ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → F = dom ⁡ F
4 f1dm ⊢ F : A ⟶ 1-1 B → dom ⁡ F = A
5 4 adantl ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → dom ⁡ F = A
6 dmexg ⊢ F ∈ V → dom ⁡ F ∈ V
7 6 adantr ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → dom ⁡ F ∈ V
8 5 7 eqeltrrd ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → A ∈ V
9 hashf1rn ⊢ A ∈ V ∧ F : A ⟶ 1-1 B → F = ran ⁡ F
10 8 9 sylancom ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → F = ran ⁡ F
11 5 fveq2d ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → dom ⁡ F = A
12 3 10 11 3eqtr3rd ⊢ F ∈ V ∧ F : A ⟶ 1-1 B → A = ran ⁡ F