Metamath Proof Explorer


Theorem hdmapg

Description: Apply the scalar sigma function (involution) G to an inner product reverses the arguments. The inner product of X and Y is represented by ( ( SY )X ) . Line 15 in Baer p. 111, f(x,y) alpha = f(y,x). (Contributed by NM, 14-Jun-2015)

Ref Expression
Hypotheses hdmapg.h ⊢ H = LHyp ⁡ K
hdmapg.u ⊢ U = DVecH ⁡ K ⁡ W
hdmapg.v ⊢ V = Base U
hdmapg.s ⊢ S = HDMap ⁡ K ⁡ W
hdmapg.g ⊢ G = HGMap ⁡ K ⁡ W
hdmapg.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmapg.x ⊢ φ → X ∈ V
hdmapg.y ⊢ φ → Y ∈ V
Assertion hdmapg ⊢ φ → G ⁡ S ⁡ Y ⁡ X = S ⁡ X ⁡ Y

Proof

Step Hyp Ref Expression
1 hdmapg.h ⊢ H = LHyp ⁡ K
2 hdmapg.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmapg.v ⊢ V = Base U
4 hdmapg.s ⊢ S = HDMap ⁡ K ⁡ W
5 hdmapg.g ⊢ G = HGMap ⁡ K ⁡ W
6 hdmapg.k ⊢ φ → K ∈ HL ∧ W ∈ H
7 hdmapg.x ⊢ φ → X ∈ V
8 hdmapg.y ⊢ φ → Y ∈ V
9 eqid ⊢ I ↾ Base K I ↾ LTrn ⁡ K ⁡ W = I ↾ Base K I ↾ LTrn ⁡ K ⁡ W
10 eqid ⊢ ocH ⁡ K ⁡ W = ocH ⁡ K ⁡ W
11 eqid ⊢ + U = + U
12 eqid ⊢ ⋅ U = ⋅ U
13 eqid ⊢ Scalar ⁡ U = Scalar ⁡ U
14 eqid ⊢ Base Scalar ⁡ U = Base Scalar ⁡ U
15 eqid ⊢ LSSum ⁡ U = LSSum ⁡ U
16 eqid ⊢ LSpan ⁡ U = LSpan ⁡ U
17 eqid ⊢ ⋅ Scalar ⁡ U = ⋅ Scalar ⁡ U
18 eqid ⊢ 0 Scalar ⁡ U = 0 Scalar ⁡ U
19 eqid ⊢ + Scalar ⁡ U = + Scalar ⁡ U
20 1 9 10 2 3 11 12 13 14 15 16 6 7 17 18 19 4 5 8 hdmapglem7 ⊢ φ → G ⁡ S ⁡ Y ⁡ X = S ⁡ X ⁡ Y