Metamath Proof Explorer


Theorem infdiffi

Description: Removing a finite set from an infinite set does not change the cardinality of the set. (Contributed by Mario Carneiro, 30-Apr-2015)

Ref Expression
Assertion infdiffi ⊢ ω ≼ A ∧ B ∈ Fin → A ∖ B ≈ A

Proof

Step Hyp Ref Expression
1 difeq2 ⊢ x = ∅ → A ∖ x = A ∖ ∅
2 dif0 ⊢ A ∖ ∅ = A
3 1 2 eqtrdi ⊢ x = ∅ → A ∖ x = A
4 3 breq1d ⊢ x = ∅ → A ∖ x ≈ A ↔ A ≈ A
5 4 imbi2d ⊢ x = ∅ → ω ≼ A → A ∖ x ≈ A ↔ ω ≼ A → A ≈ A
6 difeq2 ⊢ x = y → A ∖ x = A ∖ y
7 6 breq1d ⊢ x = y → A ∖ x ≈ A ↔ A ∖ y ≈ A
8 7 imbi2d ⊢ x = y → ω ≼ A → A ∖ x ≈ A ↔ ω ≼ A → A ∖ y ≈ A
9 difeq2 ⊢ x = y ∪ z → A ∖ x = A ∖ y ∪ z
10 difun1 ⊢ A ∖ y ∪ z = A ∖ y ∖ z
11 9 10 eqtrdi ⊢ x = y ∪ z → A ∖ x = A ∖ y ∖ z
12 11 breq1d ⊢ x = y ∪ z → A ∖ x ≈ A ↔ A ∖ y ∖ z ≈ A
13 12 imbi2d ⊢ x = y ∪ z → ω ≼ A → A ∖ x ≈ A ↔ ω ≼ A → A ∖ y ∖ z ≈ A
14 difeq2 ⊢ x = B → A ∖ x = A ∖ B
15 14 breq1d ⊢ x = B → A ∖ x ≈ A ↔ A ∖ B ≈ A
16 15 imbi2d ⊢ x = B → ω ≼ A → A ∖ x ≈ A ↔ ω ≼ A → A ∖ B ≈ A
17 reldom ⊢ Rel ⁡ ≼
18 17 brrelex2i ⊢ ω ≼ A → A ∈ V
19 enrefg ⊢ A ∈ V → A ≈ A
20 18 19 syl ⊢ ω ≼ A → A ≈ A
21 domen2 ⊢ A ∖ y ≈ A → ω ≼ A ∖ y ↔ ω ≼ A
22 21 biimparc ⊢ ω ≼ A ∧ A ∖ y ≈ A → ω ≼ A ∖ y
23 infdifsn ⊢ ω ≼ A ∖ y → A ∖ y ∖ z ≈ A ∖ y
24 22 23 syl ⊢ ω ≼ A ∧ A ∖ y ≈ A → A ∖ y ∖ z ≈ A ∖ y
25 entr ⊢ A ∖ y ∖ z ≈ A ∖ y ∧ A ∖ y ≈ A → A ∖ y ∖ z ≈ A
26 24 25 sylancom ⊢ ω ≼ A ∧ A ∖ y ≈ A → A ∖ y ∖ z ≈ A
27 26 ex ⊢ ω ≼ A → A ∖ y ≈ A → A ∖ y ∖ z ≈ A
28 27 a2i ⊢ ω ≼ A → A ∖ y ≈ A → ω ≼ A → A ∖ y ∖ z ≈ A
29 28 a1i ⊢ y ∈ Fin → ω ≼ A → A ∖ y ≈ A → ω ≼ A → A ∖ y ∖ z ≈ A
30 5 8 13 16 20 29 findcard2 ⊢ B ∈ Fin → ω ≼ A → A ∖ B ≈ A
31 30 impcom ⊢ ω ≼ A ∧ B ∈ Fin → A ∖ B ≈ A