Metamath Proof Explorer


Theorem isopn3

Description: A subset is open iff it equals its own interior. (Contributed by NM, 9-Oct-2006) (Revised by Mario Carneiro, 11-Nov-2013)

Ref Expression
Hypothesis clscld.1 ⊢ X = ⋃ J
Assertion isopn3 ⊢ J ∈ Top ∧ S ⊆ X → S ∈ J ↔ int ⁡ J ⁡ S = S

Proof

Step Hyp Ref Expression
1 clscld.1 ⊢ X = ⋃ J
2 1 ntrval ⊢ J ∈ Top ∧ S ⊆ X → int ⁡ J ⁡ S = ⋃ J ∩ 𝒫 S
3 inss2 ⊢ J ∩ 𝒫 S ⊆ 𝒫 S
4 3 unissi ⊢ ⋃ J ∩ 𝒫 S ⊆ ⋃ 𝒫 S
5 unipw ⊢ ⋃ 𝒫 S = S
6 4 5 sseqtri ⊢ ⋃ J ∩ 𝒫 S ⊆ S
7 6 a1i ⊢ S ∈ J → ⋃ J ∩ 𝒫 S ⊆ S
8 id ⊢ S ∈ J → S ∈ J
9 pwidg ⊢ S ∈ J → S ∈ 𝒫 S
10 8 9 elind ⊢ S ∈ J → S ∈ J ∩ 𝒫 S
11 elssuni ⊢ S ∈ J ∩ 𝒫 S → S ⊆ ⋃ J ∩ 𝒫 S
12 10 11 syl ⊢ S ∈ J → S ⊆ ⋃ J ∩ 𝒫 S
13 7 12 eqssd ⊢ S ∈ J → ⋃ J ∩ 𝒫 S = S
14 2 13 sylan9eq ⊢ J ∈ Top ∧ S ⊆ X ∧ S ∈ J → int ⁡ J ⁡ S = S
15 14 ex ⊢ J ∈ Top ∧ S ⊆ X → S ∈ J → int ⁡ J ⁡ S = S
16 1 ntropn ⊢ J ∈ Top ∧ S ⊆ X → int ⁡ J ⁡ S ∈ J
17 eleq1 ⊢ int ⁡ J ⁡ S = S → int ⁡ J ⁡ S ∈ J ↔ S ∈ J
18 16 17 syl5ibcom ⊢ J ∈ Top ∧ S ⊆ X → int ⁡ J ⁡ S = S → S ∈ J
19 15 18 impbid ⊢ J ∈ Top ∧ S ⊆ X → S ∈ J ↔ int ⁡ J ⁡ S = S