Metamath Proof Explorer


Theorem ispnrm

Description: The property of being perfectly normal. (Contributed by Mario Carneiro, 26-Aug-2015)

Ref Expression
Assertion ispnrm ⊢ J ∈ PNrm ↔ J ∈ Nrm ∧ Clsd ⁡ J ⊆ ran ⁡ f ∈ J ℕ ⟼ ⋂ ran ⁡ f

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ j = J → Clsd ⁡ j = Clsd ⁡ J
2 oveq1 ⊢ j = J → j ℕ = J ℕ
3 2 mpteq1d ⊢ j = J → f ∈ j ℕ ⟼ ⋂ ran ⁡ f = f ∈ J ℕ ⟼ ⋂ ran ⁡ f
4 3 rneqd ⊢ j = J → ran ⁡ f ∈ j ℕ ⟼ ⋂ ran ⁡ f = ran ⁡ f ∈ J ℕ ⟼ ⋂ ran ⁡ f
5 1 4 sseq12d ⊢ j = J → Clsd ⁡ j ⊆ ran ⁡ f ∈ j ℕ ⟼ ⋂ ran ⁡ f ↔ Clsd ⁡ J ⊆ ran ⁡ f ∈ J ℕ ⟼ ⋂ ran ⁡ f
6 df-pnrm ⊢ PNrm = j ∈ Nrm | Clsd ⁡ j ⊆ ran ⁡ f ∈ j ℕ ⟼ ⋂ ran ⁡ f
7 5 6 elrab2 ⊢ J ∈ PNrm ↔ J ∈ Nrm ∧ Clsd ⁡ J ⊆ ran ⁡ f ∈ J ℕ ⟼ ⋂ ran ⁡ f