Metamath Proof Explorer


Theorem lcm2un

Description: Least common multiple of natural numbers up to 2 equals 2. (Contributed by metakunt, 25-Apr-2024)

Ref Expression
Assertion lcm2un ⊢ lcm _ ⁡ 1 … 2 = 2

Proof

Step Hyp Ref Expression
1 2nn ⊢ 2 ∈ ℕ
2 id ⊢ 2 ∈ ℕ → 2 ∈ ℕ
3 2 lcmfunnnd ⊢ 2 ∈ ℕ → lcm _ ⁡ 1 … 2 = lcm _ ⁡ 1 … 2 − 1 lcm 2
4 1 3 ax-mp ⊢ lcm _ ⁡ 1 … 2 = lcm _ ⁡ 1 … 2 − 1 lcm 2
5 2m1e1 ⊢ 2 − 1 = 1
6 5 oveq2i ⊢ 1 … 2 − 1 = 1 … 1
7 6 fveq2i ⊢ lcm _ ⁡ 1 … 2 − 1 = lcm _ ⁡ 1 … 1
8 7 oveq1i ⊢ lcm _ ⁡ 1 … 2 − 1 lcm 2 = lcm _ ⁡ 1 … 1 lcm 2
9 4 8 eqtri ⊢ lcm _ ⁡ 1 … 2 = lcm _ ⁡ 1 … 1 lcm 2
10 lcm1un ⊢ lcm _ ⁡ 1 … 1 = 1
11 10 oveq1i ⊢ lcm _ ⁡ 1 … 1 lcm 2 = 1 lcm 2
12 1z ⊢ 1 ∈ ℤ
13 2z ⊢ 2 ∈ ℤ
14 lcmcom ⊢ 1 ∈ ℤ ∧ 2 ∈ ℤ → 1 lcm 2 = 2 lcm 1
15 12 13 14 mp2an ⊢ 1 lcm 2 = 2 lcm 1
16 lcm1 ⊢ 2 ∈ ℤ → 2 lcm 1 = 2
17 13 16 ax-mp ⊢ 2 lcm 1 = 2
18 2re ⊢ 2 ∈ ℝ
19 0le2 ⊢ 0 ≤ 2
20 18 19 pm3.2i ⊢ 2 ∈ ℝ ∧ 0 ≤ 2
21 absid ⊢ 2 ∈ ℝ ∧ 0 ≤ 2 → 2 = 2
22 20 21 ax-mp ⊢ 2 = 2
23 17 22 eqtri ⊢ 2 lcm 1 = 2
24 15 23 eqtri ⊢ 1 lcm 2 = 2
25 11 24 eqtri ⊢ lcm _ ⁡ 1 … 1 lcm 2 = 2
26 9 25 eqtri ⊢ lcm _ ⁡ 1 … 2 = 2