Metamath Proof Explorer


Theorem lduallkr3

Description: The kernels of nonzero functionals are hyperplanes. (Contributed by NM, 22-Feb-2015)

Ref Expression
Hypotheses lduallkr3.h ⊢ H = LSHyp ⁡ W
lduallkr3.f ⊢ F = LFnl ⁡ W
lduallkr3.k ⊢ K = LKer ⁡ W
lduallkr3.d ⊢ D = LDual ⁡ W
lduallkr3.o ⊢ 0 ˙ = 0 D
lduallkr3.w ⊢ φ → W ∈ LVec
lduallkr3.g ⊢ φ → G ∈ F
Assertion lduallkr3 ⊢ φ → K ⁡ G ∈ H ↔ G ≠ 0 ˙

Proof

Step Hyp Ref Expression
1 lduallkr3.h ⊢ H = LSHyp ⁡ W
2 lduallkr3.f ⊢ F = LFnl ⁡ W
3 lduallkr3.k ⊢ K = LKer ⁡ W
4 lduallkr3.d ⊢ D = LDual ⁡ W
5 lduallkr3.o ⊢ 0 ˙ = 0 D
6 lduallkr3.w ⊢ φ → W ∈ LVec
7 lduallkr3.g ⊢ φ → G ∈ F
8 eqid ⊢ Base W = Base W
9 eqid ⊢ Scalar ⁡ W = Scalar ⁡ W
10 eqid ⊢ 0 Scalar ⁡ W = 0 Scalar ⁡ W
11 8 9 10 1 2 3 6 7 lkrshp3 ⊢ φ → K ⁡ G ∈ H ↔ G ≠ Base W × 0 Scalar ⁡ W
12 lveclmod ⊢ W ∈ LVec → W ∈ LMod
13 6 12 syl ⊢ φ → W ∈ LMod
14 8 9 10 4 5 13 ldual0v ⊢ φ → 0 ˙ = Base W × 0 Scalar ⁡ W
15 14 neeq2d ⊢ φ → G ≠ 0 ˙ ↔ G ≠ Base W × 0 Scalar ⁡ W
16 11 15 bitr4d ⊢ φ → K ⁡ G ∈ H ↔ G ≠ 0 ˙