Metamath Proof Explorer


Theorem lidldomnnring

Description: A (left) ideal of a domain which is neither the zero ideal nor the unit ideal is not a unital ring. (Contributed by AV, 18-Feb-2020)

Ref Expression
Hypotheses lidlabl.l ⊢ L = LIdeal ⁡ R
lidlabl.i ⊢ I = R ↾ 𝑠 U
zlidlring.b ⊢ B = Base R
zlidlring.0 ⊢ 0 ˙ = 0 R
Assertion lidldomnnring ⊢ R ∈ Domn ∧ U ∈ L ∧ U ≠ 0 ˙ ∧ U ≠ B → I ∉ Ring

Proof

Step Hyp Ref Expression
1 lidlabl.l ⊢ L = LIdeal ⁡ R
2 lidlabl.i ⊢ I = R ↾ 𝑠 U
3 zlidlring.b ⊢ B = Base R
4 zlidlring.0 ⊢ 0 ˙ = 0 R
5 neanior ⊢ U ≠ 0 ˙ ∧ U ≠ B ↔ ¬ U = 0 ˙ ∨ U = B
6 5 biimpi ⊢ U ≠ 0 ˙ ∧ U ≠ B → ¬ U = 0 ˙ ∨ U = B
7 6 3adant1 ⊢ U ∈ L ∧ U ≠ 0 ˙ ∧ U ≠ B → ¬ U = 0 ˙ ∨ U = B
8 7 adantl ⊢ R ∈ Domn ∧ U ∈ L ∧ U ≠ 0 ˙ ∧ U ≠ B → ¬ U = 0 ˙ ∨ U = B
9 df-nel ⊢ I ∉ Ring ↔ ¬ I ∈ Ring
10 1 2 3 4 uzlidlring ⊢ R ∈ Domn ∧ U ∈ L → I ∈ Ring ↔ U = 0 ˙ ∨ U = B
11 10 3ad2antr1 ⊢ R ∈ Domn ∧ U ∈ L ∧ U ≠ 0 ˙ ∧ U ≠ B → I ∈ Ring ↔ U = 0 ˙ ∨ U = B
12 11 notbid ⊢ R ∈ Domn ∧ U ∈ L ∧ U ≠ 0 ˙ ∧ U ≠ B → ¬ I ∈ Ring ↔ ¬ U = 0 ˙ ∨ U = B
13 9 12 bitrid ⊢ R ∈ Domn ∧ U ∈ L ∧ U ≠ 0 ˙ ∧ U ≠ B → I ∉ Ring ↔ ¬ U = 0 ˙ ∨ U = B
14 8 13 mpbird ⊢ R ∈ Domn ∧ U ∈ L ∧ U ≠ 0 ˙ ∧ U ≠ B → I ∉ Ring