Metamath Proof Explorer


Theorem lineq

Description: Solution of a (scalar) linear equation. (Contributed by BJ, 6-Jun-2019)

Ref Expression
Hypotheses lineq.a ⊢ φ → A ∈ ℂ
lineq.b ⊢ φ → B ∈ ℂ
lineq.x ⊢ φ → X ∈ ℂ
lineq.y ⊢ φ → Y ∈ ℂ
lineq.n0 ⊢ φ → A ≠ 0
Assertion lineq ⊢ φ → A ⁢ X + B = Y ↔ X = Y − B A

Proof

Step Hyp Ref Expression
1 lineq.a ⊢ φ → A ∈ ℂ
2 lineq.b ⊢ φ → B ∈ ℂ
3 lineq.x ⊢ φ → X ∈ ℂ
4 lineq.y ⊢ φ → Y ∈ ℂ
5 lineq.n0 ⊢ φ → A ≠ 0
6 1 3 mulcld ⊢ φ → A ⁢ X ∈ ℂ
7 6 2 4 addlsub ⊢ φ → A ⁢ X + B = Y ↔ A ⁢ X = Y − B
8 4 2 subcld ⊢ φ → Y − B ∈ ℂ
9 1 3 8 5 rdiv ⊢ φ → A ⁢ X = Y − B ↔ X = Y − B A
10 7 9 bitrd ⊢ φ → A ⁢ X + B = Y ↔ X = Y − B A