Metamath Proof Explorer


Theorem lmhmlin

Description: A homomorphism of left modules is K -linear. (Contributed by Stefan O'Rear, 1-Jan-2015)

Ref Expression
Hypotheses lmhmlin.k ⊢ K = Scalar ⁡ S
lmhmlin.b ⊢ B = Base K
lmhmlin.e ⊢ E = Base S
lmhmlin.m ⊢ · ˙ = ⋅ S
lmhmlin.n ⊢ × ˙ = ⋅ T
Assertion lmhmlin ⊢ F ∈ S LMHom T ∧ X ∈ B ∧ Y ∈ E → F ⁡ X · ˙ Y = X × ˙ F ⁡ Y

Proof

Step Hyp Ref Expression
1 lmhmlin.k ⊢ K = Scalar ⁡ S
2 lmhmlin.b ⊢ B = Base K
3 lmhmlin.e ⊢ E = Base S
4 lmhmlin.m ⊢ · ˙ = ⋅ S
5 lmhmlin.n ⊢ × ˙ = ⋅ T
6 eqid ⊢ Scalar ⁡ T = Scalar ⁡ T
7 1 6 2 3 4 5 islmhm ⊢ F ∈ S LMHom T ↔ S ∈ LMod ∧ T ∈ LMod ∧ F ∈ S GrpHom T ∧ Scalar ⁡ T = K ∧ ∀ a ∈ B ∀ b ∈ E F ⁡ a · ˙ b = a × ˙ F ⁡ b
8 7 simprbi ⊢ F ∈ S LMHom T → F ∈ S GrpHom T ∧ Scalar ⁡ T = K ∧ ∀ a ∈ B ∀ b ∈ E F ⁡ a · ˙ b = a × ˙ F ⁡ b
9 8 simp3d ⊢ F ∈ S LMHom T → ∀ a ∈ B ∀ b ∈ E F ⁡ a · ˙ b = a × ˙ F ⁡ b
10 fvoveq1 ⊢ a = X → F ⁡ a · ˙ b = F ⁡ X · ˙ b
11 oveq1 ⊢ a = X → a × ˙ F ⁡ b = X × ˙ F ⁡ b
12 10 11 eqeq12d ⊢ a = X → F ⁡ a · ˙ b = a × ˙ F ⁡ b ↔ F ⁡ X · ˙ b = X × ˙ F ⁡ b
13 oveq2 ⊢ b = Y → X · ˙ b = X · ˙ Y
14 13 fveq2d ⊢ b = Y → F ⁡ X · ˙ b = F ⁡ X · ˙ Y
15 fveq2 ⊢ b = Y → F ⁡ b = F ⁡ Y
16 15 oveq2d ⊢ b = Y → X × ˙ F ⁡ b = X × ˙ F ⁡ Y
17 14 16 eqeq12d ⊢ b = Y → F ⁡ X · ˙ b = X × ˙ F ⁡ b ↔ F ⁡ X · ˙ Y = X × ˙ F ⁡ Y
18 12 17 rspc2v ⊢ X ∈ B ∧ Y ∈ E → ∀ a ∈ B ∀ b ∈ E F ⁡ a · ˙ b = a × ˙ F ⁡ b → F ⁡ X · ˙ Y = X × ˙ F ⁡ Y
19 9 18 syl5com ⊢ F ∈ S LMHom T → X ∈ B ∧ Y ∈ E → F ⁡ X · ˙ Y = X × ˙ F ⁡ Y
20 19 3impib ⊢ F ∈ S LMHom T ∧ X ∈ B ∧ Y ∈ E → F ⁡ X · ˙ Y = X × ˙ F ⁡ Y