Metamath Proof Explorer


Theorem lmlim

Description: Relate a limit in a given topology to a complex number limit, provided that topology agrees with the common topology on CC on the required subset. (Contributed by Thierry Arnoux, 11-Jul-2017)

Ref Expression
Hypotheses lmlim.j ⊢ J ∈ TopOn ⁡ Y
lmlim.f ⊢ φ → F : ℕ ⟶ X
lmlim.p ⊢ φ → P ∈ X
lmlim.t ⊢ J ↾ 𝑡 X = TopOpen ⁡ ℂ fld ↾ 𝑡 X
lmlim.x ⊢ X ⊆ ℂ
Assertion lmlim ⊢ φ → F ⇝t ⁡ J P ↔ F ⇝ P

Proof

Step Hyp Ref Expression
1 lmlim.j ⊢ J ∈ TopOn ⁡ Y
2 lmlim.f ⊢ φ → F : ℕ ⟶ X
3 lmlim.p ⊢ φ → P ∈ X
4 lmlim.t ⊢ J ↾ 𝑡 X = TopOpen ⁡ ℂ fld ↾ 𝑡 X
5 lmlim.x ⊢ X ⊆ ℂ
6 eqid ⊢ J ↾ 𝑡 X = J ↾ 𝑡 X
7 nnuz ⊢ ℕ = ℤ ≥ 1
8 cnex ⊢ ℂ ∈ V
9 8 a1i ⊢ φ → ℂ ∈ V
10 5 a1i ⊢ φ → X ⊆ ℂ
11 9 10 ssexd ⊢ φ → X ∈ V
12 1 topontopi ⊢ J ∈ Top
13 12 a1i ⊢ φ → J ∈ Top
14 1z ⊢ 1 ∈ ℤ
15 14 a1i ⊢ φ → 1 ∈ ℤ
16 6 7 11 13 3 15 2 lmss ⊢ φ → F ⇝t ⁡ J P ↔ F ⇝t ⁡ J ↾ 𝑡 X P
17 4 fveq2i ⊢ ⇝t ⁡ J ↾ 𝑡 X = ⇝t ⁡ TopOpen ⁡ ℂ fld ↾ 𝑡 X
18 17 breqi ⊢ F ⇝t ⁡ J ↾ 𝑡 X P ↔ F ⇝t ⁡ TopOpen ⁡ ℂ fld ↾ 𝑡 X P
19 18 a1i ⊢ φ → F ⇝t ⁡ J ↾ 𝑡 X P ↔ F ⇝t ⁡ TopOpen ⁡ ℂ fld ↾ 𝑡 X P
20 eqid ⊢ TopOpen ⁡ ℂ fld ↾ 𝑡 X = TopOpen ⁡ ℂ fld ↾ 𝑡 X
21 eqid ⊢ TopOpen ⁡ ℂ fld = TopOpen ⁡ ℂ fld
22 21 cnfldtop ⊢ TopOpen ⁡ ℂ fld ∈ Top
23 22 a1i ⊢ φ → TopOpen ⁡ ℂ fld ∈ Top
24 20 7 11 23 3 15 2 lmss ⊢ φ → F ⇝t ⁡ TopOpen ⁡ ℂ fld P ↔ F ⇝t ⁡ TopOpen ⁡ ℂ fld ↾ 𝑡 X P
25 fss ⊢ F : ℕ ⟶ X ∧ X ⊆ ℂ → F : ℕ ⟶ ℂ
26 2 5 25 sylancl ⊢ φ → F : ℕ ⟶ ℂ
27 21 7 lmclimf ⊢ 1 ∈ ℤ ∧ F : ℕ ⟶ ℂ → F ⇝t ⁡ TopOpen ⁡ ℂ fld P ↔ F ⇝ P
28 14 26 27 sylancr ⊢ φ → F ⇝t ⁡ TopOpen ⁡ ℂ fld P ↔ F ⇝ P
29 24 28 bitr3d ⊢ φ → F ⇝t ⁡ TopOpen ⁡ ℂ fld ↾ 𝑡 X P ↔ F ⇝ P
30 16 19 29 3bitrd ⊢ φ → F ⇝t ⁡ J P ↔ F ⇝ P