Metamath Proof Explorer


Theorem logeq0im1

Description: If the logarithm of a number is 0, the number must be 1. (Contributed by David A. Wheeler, 22-Jul-2017)

Ref Expression
Assertion logeq0im1 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ log ⁡ A = 0 → A = 1

Proof

Step Hyp Ref Expression
1 eflog ⊢ A ∈ ℂ ∧ A ≠ 0 → e log ⁡ A = A
2 1 3adant3 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ log ⁡ A = 0 → e log ⁡ A = A
3 fveq2 ⊢ log ⁡ A = 0 → e log ⁡ A = e 0
4 ef0 ⊢ e 0 = 1
5 3 4 eqtrdi ⊢ log ⁡ A = 0 → e log ⁡ A = 1
6 5 3ad2ant3 ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ log ⁡ A = 0 → e log ⁡ A = 1
7 2 6 eqtr3d ⊢ A ∈ ℂ ∧ A ≠ 0 ∧ log ⁡ A = 0 → A = 1