Metamath Proof Explorer


Theorem lpadlem3

Description: Lemma for lpadlen1 . (Contributed by Thierry Arnoux, 7-Aug-2023)

Ref Expression
Hypotheses lpadlen.1 ⊢ φ → L ∈ ℕ 0
lpadlen.2 ⊢ φ → W ∈ Word S
lpadlen.3 ⊢ φ → C ∈ S
lpadlen1.1 ⊢ φ → L ≤ W
Assertion lpadlem3 ⊢ φ → 0 ..^ L − W × C = ∅

Proof

Step Hyp Ref Expression
1 lpadlen.1 ⊢ φ → L ∈ ℕ 0
2 lpadlen.2 ⊢ φ → W ∈ Word S
3 lpadlen.3 ⊢ φ → C ∈ S
4 lpadlen1.1 ⊢ φ → L ≤ W
5 lencl ⊢ W ∈ Word S → W ∈ ℕ 0
6 2 5 syl ⊢ φ → W ∈ ℕ 0
7 6 nn0zd ⊢ φ → W ∈ ℤ
8 1 nn0zd ⊢ φ → L ∈ ℤ
9 fzo0n ⊢ W ∈ ℤ ∧ L ∈ ℤ → L ≤ W ↔ 0 ..^ L − W = ∅
10 9 biimpa ⊢ W ∈ ℤ ∧ L ∈ ℤ ∧ L ≤ W → 0 ..^ L − W = ∅
11 7 8 4 10 syl21anc ⊢ φ → 0 ..^ L − W = ∅
12 11 xpeq1d ⊢ φ → 0 ..^ L − W × C = ∅ × C
13 0xp ⊢ ∅ × C = ∅
14 12 13 eqtrdi ⊢ φ → 0 ..^ L − W × C = ∅